Question

我正在尝试调用RESTful Web服务来获取JSON对象。现在我尝试通过HttpGet进行调用并获得成功。我需要传递的URL非常类似：http://example.com/ /def.xxx?Name=save&Code=sample&OrderDetails=[{Count“：”2“，”ID“：”1“， “价格”：“5”}]。我

`

StringBuilder URL = new StringBuilder("http://example.com/def.xxx?");
URL.append("Name="+name+"&");
URL.append("Code="+code+"&");
URL.append("Details=%5b");
            int val = 0;
            for (int i = 0; i<len; i++){
                    if (val > 0)
                    {URL.append(",");
                    }
                    else
                        val = 1;                
            URL.append(.....);
URLX = URL.toString();
httpGet = new HttpGet(URLX); 
response = client1.execute(httpGet);

`

现在，如果我想进行HttpPost调用而不是HttpGet调用，该怎么办？我试过这种方式，

String URL = "http://example.com/def.xxx";

    DefaultHttpClient client1 = new DefaultHttpClient();
    HttpResponse response = null;
    HttpPost httpPost = new HttpPost();
    ArrayList<NameValue> postParameters;

    postParameters = new ArrayList<NameValuePair>();
        postParameters.add(new BasicNameValuePair("Name", name));
        postParameters.add(new BasicNameValuePair("Code", code));

try {
            httpPost.setEntity(new UrlEncodedFormEntity(postParameters));
            } catch (UnsupportedEncodingException e1) {
                // TODO Auto-generated catch block
                e1.printStackTrace();
            }


                response = client1.execute(httpPost);

} 现在我不确定如何在Post调用中添加Details = [{“Count”：“2”，“ID”：“1”，“Price”：“5”}]中的值对，我该怎么办？执行它以获得与我在进行HttpGet调用时获得的相同JSON对象。请帮忙。

Answer 1

DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);

ArrayList<NameValuePair> postParameters;

postParameters = new ArrayList<NameValuePair>();
postParameters.add(new BasicNameValuePair("Name", name));
postParameters.add(new BasicNameValuePair("Code", sample));

构造JSONArray或JSONObject您可以checkit。

postParameters.add(new BasicNameValuePair("OrderDetails",jOrderdetails));

httpPost.setEntity(new UrlEncodedFormEntity(params));
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();

修改： -

对于OrderDetailsObject，您可以按如下方式构造它。

JSONArray jOrderdetails = new JSONArray(); for(int i=0;i<len;i++){ JSONObject childObject = new JSONObject(); childObject.put("Count",countvalue); childObject.put("ID",IDvalue); childObject.put("Price",Pricevalue); jOrderdetails.put(childObject).toString(); }

以上面显示的方式，你可以构造JSONArray，然后你需要作为参数传递该对象。

如何向RESTful Web服务发出Http Post请求以传递包含值数组的参数的URL？

1 个答案: