Question

我想将'Open_Buffer_Continue'函数添加到MediaInfoDLL.py ctypes包装器中，绑定是here和 MediaInfoDLL.cs C＃绑定已经实现了这个功能，所以它是可能的。

我如何通过以下内容：

file = open('./file.avi', 'rb')

到期望的mediainfo cpp Open_Buffer_Continue：

(   const ZenLib::int8u *   Buffer,
    size_t                  Buffer_Size 
)

这是我到目前为止所做的：

MediaInfo_Open_Buffer_Init = MediaInfoDLL_Handler.MediaInfo_Open_Buffer_Init
MediaInfo_Open_Buffer_Init.argtype = [c_size_t, c_size_t]
MediaInfo_Open_Buffer_Init.restype = None

MediaInfo_Open_Buffer_Continue = MediaInfoDLL_Handler.MediaInfo_Open_Buffer_Continue
MediaInfo_Open_Buffer_Continue.argtype = [c_size_t, c_size_t]  # NOT SURE HERE var 1
MediaInfo_Open_Buffer_Continue.restype = c_size_t

MediaInfo_Open_Buffer_Finalize = MediaInfoDLL_Handler.MediaInfo_Open_Buffer_Finalize
MediaInfo_Open_Buffer_Finalize.argtype = [c_void_p]
MediaInfo_Open_Buffer_Finalize.restype = None

Answer 1

我对mediainfo一无所知，但看起来ZenLib::int8u*是指向字节的指针，所以最好用的是：

MediaInfo_Open_Buffer_Continue.argtype = [c_char_p, c_size_t]

然后将您的文件读入字符串并传递它：

with open('./file.avi','rb') as f:
    data = f.read()
MediaInfo_Open_Buffer_Continue(data,len(data))

如何将'文件'传递给cpp函数，该函数需要Python ctypes中的'Buffer'？

1 个答案: