Question

我正在监视我的应用程序中的Pitch and Roll值，我想监视它是否在一秒钟内改变5度，然后运行一个进程。目前我的代码如下所示：

 CMAttitude *attitude;
CMDeviceMotion *motion = scoringManage.deviceMotion;
attitude = motion.attitude;
basePitch = degrees(attitude.pitch);
baseRoll = degrees(attitude.roll);

if((pitchfloat >= basePitch+5) || (pitchfloat <= basePitch-5)) {


}
if((rollfloat >= baseRoll+5) || (rollfloat <= baseRoll-5)) {

}

这称为：

yprTime = [NSTimer scheduledTimerWithTimeInterval:(1.0/1.0) target:self selector:@selector(yprscore) userInfo:nil repeats:YES];

此过程每秒都会与我的计时器一起运行，但是当值更改时，它将多次运行该循环。

问题是if语句在那一秒内运行的次数太多了20次。

Answer 1

如果您只想在值更改后运行它，则需要设置BOOL。在你的if pitch＆gt;中5语句设置另一个如果检查BOOL

if((pitchfloat >= basePitch+5) || (pitchfloat <= basePitch-5)) {
 if (firstTimeBOOLCheckisTrue == NO) {

 firstTimeBOOLCheckisTrue = YES;

 [self doSomething];
    }
}


(void *)doSomething{

if (imReadytoCheckPitchAgain == YES){
firstTimeBOOLCheckisTrue = NO;

}

如何检查值是否在一秒内改变了一定量？

1 个答案: