我对此WPF-xaml代码有疑问。没有使用xaml很多,但设法得到我想要的代码。但我觉得这根本不是好习惯。首先,我想根据某个单元格中的某些值将行从红色更改为绿色或灰色。我是否真的必须为每个单元保留一个触发器,或者无论如何都要在整行上执行相同的触发器?我还想在选择行时设置特定颜色,但样式似乎不支持“IsSelected”......
<DataGrid AutoGenerateColumns="False" IsReadOnly="True" HorizontalAlignment="Stretch" Margin="200,50,5,5" ItemsSource="{Binding}" Name="dataGrid1" VerticalAlignment="Stretch" EnableRowVirtualization="True" SelectionChanged="dataGrid1_SelectionChanged" MouseDoubleClick="dataGrid1_MouseDoubleClick">
<DataGrid.Columns>
<DataGridTextColumn Width="1*" Header="File name" Binding="{Binding Path=Filename}">
<DataGridTextColumn.ElementStyle>
<Style TargetType="{x:Type TextBlock}">
<Setter Property="Background" Value="#68FF0000" />
<Style.Triggers>
<DataTrigger Binding="{Binding Errorcode}" Value="0">
<Setter Property="Background" Value="LightGreen"/>
</DataTrigger>
<DataTrigger Binding="{Binding Filename}" Value="File not created">
<Setter Property="Background" Value="LightGray" />
</DataTrigger>
</Style.Triggers>
</Style>
</DataGridTextColumn.ElementStyle>
</DataGridTextColumn>
<DataGridTextColumn Width="1*" Header="Weight" Binding="{Binding Path=Info1}">
<DataGridTextColumn.ElementStyle>
<Style TargetType="{x:Type TextBlock}">
<Setter Property="Background" Value="#68FF0000" />
<Style.Triggers>
<DataTrigger Binding="{Binding Errorcode}" Value="0">
<Setter Property="Background" Value="LightGreen" />
</DataTrigger>
<DataTrigger Binding="{Binding Filename}" Value="File not created">
<Setter Property="Background" Value="LightGray" />
</DataTrigger>
</Style.Triggers>
</Style>
</DataGridTextColumn.ElementStyle>
</DataGridTextColumn>
<DataGridTextColumn Width="1*" Header="Rfid" Binding="{Binding Path=Info1}">
<DataGridTextColumn.ElementStyle>
<Style TargetType="{x:Type TextBlock}">
<Setter Property="Background" Value="#68FF0000" />
<Style.Triggers>
<DataTrigger Binding="{Binding Errorcode}" Value="0">
<Setter Property="Background" Value="LightGreen" />
</DataTrigger>
<DataTrigger Binding="{Binding Filename}" Value="File not created">
<Setter Property="Background" Value="LightGray" />
</DataTrigger>
</Style.Triggers>
</Style>
</DataGridTextColumn.ElementStyle>
</DataGridTextColumn>
<DataGridTextColumn Width="1*" Header="Date/Time" Binding="{Binding Datetime, StringFormat=\{0:yyyy.MM.dd HH:mm:ss\}}">
<DataGridTextColumn.ElementStyle>
<Style TargetType="{x:Type TextBlock}">
<Setter Property="Background" Value="#68FF0000" />
<Style.Triggers>
<DataTrigger Binding="{Binding Errorcode}" Value="0">
<Setter Property="Background" Value="LightGreen" />
</DataTrigger>
<DataTrigger Binding="{Binding Filename}" Value="File not created">
<Setter Property="Background" Value="LightGray" />
</DataTrigger>
</Style.Triggers>
</Style>
</DataGridTextColumn.ElementStyle>
</DataGridTextColumn>
<DataGridTextColumn Width="1*" Header="Error code" Binding="{Binding Path=Errorcode}">
<DataGridTextColumn.ElementStyle>
<Style TargetType="{x:Type TextBlock}">
<Setter Property="Background" Value="#68FF0000" />
<Style.Triggers>
<DataTrigger Binding="{Binding Errorcode}" Value="0">
<Setter Property="Background" Value="LightGreen" />
</DataTrigger>
<DataTrigger Binding="{Binding Filename}" Value="File not created">
<Setter Property="Background" Value="LightGray" />
</DataTrigger>
</Style.Triggers>
</Style>
</DataGridTextColumn.ElementStyle>
</DataGridTextColumn>
</DataGrid.Columns>
</DataGrid>
答案 0 :(得分:2)
我对DataGrid
不是很有经验,所以这可能不是最好的选择,但我认为你可以通过设置Row的样式而不是单个列来实现你所追求的目标。 :
<DataGrid <!-- Your settings here -->>
<!-- Your column definitions here -->
<DataGrid.RowStyle>
<Style TargetType="DataGridRow">
<Style.Triggers>
<DataTrigger Binding="{Binding Path=Errorcode}" Value="0">
<Setter Property="Background" Value="LightGreen" />
<!-- Other Setters -->
</DataTrigger>
<DataTrigger Binding="{Binding Path=Filename}" Value="File not created">
<Setter Property="Background" Value="LightGray" />
</DataTrigger>
<!-- Other Triggers -->
<Trigger Property="IsSelected" Value="True">
<Setter Property="Background" Value="Red" />
<!-- Other Setters -->
</Trigger>
</Style.Triggers>
</Style>
</DataGrid.RowStyle>
</DataGrid>
祝你好运。