Question

我正在尝试创建一个本机登录屏幕，其中用户名和密码框在处理请求时滑出屏幕（如果登录失败，则向上滑动）。

为了实现这一点，我已经定义了我的动画（DropDownAnimation）并将其分配给我的LinearLayout（页脚）。当用户单击“登录”按钮时，我启动动画，然后调用启动tryLogin()的函数（AsyncTask）。 AsyncTask处理创建和发送登录请求以及获得JSONObject响应的所有工作。

但是，我的问题是slideDown动画直到AsyncTask完成后才开始。成功登录时看起来并不是那么糟糕，但是登录失败意味着LinearLayout永远不会向下滑动 - 它跳到屏幕底部，开始slideUp动画回到原来的位置。

这似乎与this question类似，但我没有使用bindService()，我的所有非UI代码似乎（对我来说）都包含在AsyncTask中已经。 LogCat告诉我：

06-24 04:37:35.141: I/Choreographer(5347): Skipped 137 frames! The application may be doing too much work on its main thread.

我认为这些是页脚向下滑动的框架 - 但我无法弄清楚我在主线程上执行的是什么。这是我的LoginPage和LoginTask的代码。

LoginPage.java

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_login_page);

    login = (Button) findViewById(R.id.login);
    username = (EditText) findViewById(R.id.username);
    password = (EditText) findViewById(R.id.password);
    footer = (LinearLayout) findViewById(R.id.footer);

    // We must wait for the layout to be finalised before trying to find heights.
    ViewTreeObserver vto = footer.getViewTreeObserver();
    vto.addOnGlobalLayoutListener(new OnGlobalLayoutListener() {
        @Override
        public void onGlobalLayout() {
            initAnimations();
        }
    });

    loading = (TextView) findViewById(R.id.loading);

    login.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            String mUsername = username.getText().toString();
            String mPassword = password.getText().toString();

                            // Neither of these two things happen until after LoginTask is done.
            footer.startAnimation(slideDown);
            loading.setVisibility(TextView.VISIBLE);

            tryLogin(mUsername, mPassword);
        }
    });
}

protected void tryLogin(String mUsername, String mPassword) {
    Exception e;
    String loginUrl = getString(R.string.login_url);
    String clientId = getString(R.string.client_id);
    String clientSecret = getString(R.string.client_secret);
    LoginTask loginTask = (LoginTask) new LoginTask().execute(mUsername, mPassword, loginUrl, clientId, clientSecret);
    if ((e = loginTask.getException()) != null) {
        Toast.makeText(this, e.toString(), Toast.LENGTH_LONG).show();
        Toast.makeText(this, e.getMessage(), Toast.LENGTH_LONG).show();
    } else {
        JSONObject response;
        try {
            response = loginTask.get();
            Log.d("login", response.toString());
            if (!response.has("access_token")) {
                loading.setVisibility(TextView.INVISIBLE);
                footer.startAnimation(slideUp);
                Toast.makeText(this, "Login error", Toast.LENGTH_LONG).show();
            } else {
                Intent i = new Intent(this, FullscreenWebView.class);
                i.putExtra("accessToken", response.get("access_token").toString());
                startActivity(i);
                overridePendingTransition(0, 0);
            }
        } catch (InterruptedException e1) {
            e1.printStackTrace();
            Thread.currentThread().interrupt();
        } catch (ExecutionException e1) {
            e1.printStackTrace();
        } catch (JSONException e1) {
            e1.printStackTrace();
            throw new RuntimeException(e);
        }
    }
}

LoginTask.java

class LoginTask extends AsyncTask<String, Void, JSONObject> {
    private Exception exception;

    @Override
    protected JSONObject doInBackground(String... params) {
        HttpURLConnection connection;
        OutputStreamWriter request = null;

        URL url = null;
        JSONObject response = null;
        String parameters = "grant_type=password&username="+params[0]+"&password="+params[1]+"&client_id="+params[3]+"&client_secret="+params[4];

        try {
            url = new URL(params[2]);
            connection = (HttpURLConnection) url.openConnection();
            connection.setDoOutput(true);
            connection.setRequestProperty("Content-type", "application/x-www-form-urlencoded");
            connection.setRequestMethod("POST");

            request = new OutputStreamWriter(connection.getOutputStream());
            request.write(parameters);
            request.flush();
            request.close();

            // username or password is probably wrong
            Log.d("login", ""+connection.getResponseCode());
            if (connection.getResponseCode() != 200) {
                return new JSONObject();
            }
            String line = "";
            InputStreamReader isr = new InputStreamReader(connection.getInputStream());
            BufferedReader reader = new BufferedReader(isr);
            StringBuilder sb = new StringBuilder();
            while ((line = reader.readLine()) != null) {
                sb.append(line + "\n");
            }

            Log.d("login", sb.toString());
            response = new JSONObject(sb.toString());

            isr.close();
            reader.close();
        } catch (Exception e) {
            this.exception = e;
        }

        return response;
    }
}

我也尝试让LoginTask成为LoginPage的成员类，并在onPreExecute()方法中启动动画，但这并未改变任何内容。

非常感谢任何帮助！

Answer 1

使用AsyncTask.get()时，您正在阻止UI线程。当动画在UI线程上运行时，它看起来好像没有运行（实际上它被长时间运行的tryLogin方法阻止）。

相反，您应该将依赖于LoginTask结果的代码移动到其onPostExecute方法：

protected void tryLogin(String mUsername, String mPassword) {
    String loginUrl = getString(R.string.login_url);
    String clientId = getString(R.string.client_id);
    String clientSecret = getString(R.string.client_secret);
    new LoginTask().execute(mUsername, mPassword, 
        loginUrl, clientId, clientSecret);
}

<强> LoginTask.java

class LoginTask extends AsyncTask<String, Void, JSONObject> {
    private Exception exception;

    @Override
    protected JSONObject doInBackground(String... params) {
        // Unchanged
    }

    public void onPostExecute(JSONObject response) {
        if (exception != null) {
            Toast.makeText(this, e.toString(), Toast.LENGTH_LONG).show();
            Toast.makeText(this, e.getMessage(), Toast.LENGTH_LONG).show();
        } else {
            Log.d("login", response.toString());
            if (!response.has("access_token")) {
                loading.setVisibility(TextView.INVISIBLE);
                footer.startAnimation(slideUp);
                Toast.makeText(this, "Login error", Toast.LENGTH_LONG).show();
            } else {
                Intent i = new Intent(this, FullscreenWebView.class);
                i.putExtra("accessToken", response.get("access_token").toString());
                startActivity(i);
                overridePendingTransition(0, 0);
            }
        }
    }
}

Android动画仅在AsyncTask完成后启动

1 个答案: