我是Java的新手,我创建了一些迷你游戏,我希望玩家选择是否想要再次玩游戏,我尝试将我的开始布尔变量更改为静态类型并添加一些行代码,但代码似乎不起作用,每次我玩游戏,它确实问我是否要重播,但问题是,即使我最后在控制台输入“是”,游戏似乎没有重启。任何人都可以帮助我,我真的很感激,谢谢!
import java.util.Random;
import java.util.Scanner;
//Rocks, papers, scissors game complied by William To.
public class RockPaperScissor {
static int gamePlays = 0;
static boolean start = true;
public static void main(String[] args) {
while (start){
@SuppressWarnings("resource")
Scanner userInput = new Scanner(System.in);
Random comOutput = new Random();
System.out.println("Do you choose rock, paper or scissor?");
String userChoice = userInput.nextLine();
int comChoice = comOutput.nextInt(2);
switch (userChoice){
case "rock":
if(comChoice == 0){
System.out.println("I choose rock too! That's a draw!");
} else if(comChoice == 1){
System.out.println("I choose paper! I win!");
} else {
System.out.println("I choose scissor! You win!");
}
break;
case "paper":
if(comChoice == 0){
System.out.println("I choose rock! You win!");
} else if(comChoice == 1){
System.out.println("I choose paper too! That's a draw!");
} else {
System.out.println("I choose scissor! I win!");
}
break;
case "scissor":
if(comChoice == 0){
System.out.println("I choose rock! I win!");
} else if(comChoice == 1){
System.out.println("I choose paper! You win!");
} else {
System.out.println("I choose scissor too! That's a draw!");
}
break;
default :
System.out.println("I don't think that's an option.");
break;
}
gamePlays++;
System.out.println("You've played " + gamePlays + " games.");
//BELOW IS THE PART I want to ask, what's wrong?
System.out.println("Do you want to play again?");
String playAgain = userInput.next();
if (playAgain == "yes"){
System.out.println("Restarting game...");
start = true;
} else if (playAgain == "no") {
System.out.println("Quitting game.");
start = false;
}
}
}
}
从Eclipse打印出来:
Do you choose rock, paper or scissor?
rock **//my input**
I choose paper! I win!
You've played 1 games.
Do you want to play again?
yes **//my input**
Do you choose rock, paper or scissor?
paper **//my input**
I choose paper too! That's a draw!
You've played 2 games.
Do you want to play again?
no **//my input**
Do you choose rock, paper or scissor?
答案 0 :(得分:4)
尝试:
if ("yes".equals(playAgain)) {
System.out.println("Restarting game...");
start = true;
} else if ("no".equals(playAgain)) {
System.out.println("Quitting game.");
start = false;
}
String#equals()检查字符串的字符相等性,==
检查内存引用。
答案 1 :(得分:3)
字符串之间的比较需要String#equals而不是==
。所以这个:
if (playAgain == "yes"){
System.out.println("Restarting game...");
start = true;
} else if (playAgain == "no") {
System.out.println("Quitting game.");
start = false;
}
必须成为这个:
if (playAgain.equals("yes")){
System.out.println("Restarting game...");
start = true;
} else if (playAgain.equals("no")) {
System.out.println("Quitting game.");
start = false;
}
为了正常工作。
但是,我建议使用String#equalsIgnoreCase,因为对于equals
,比较区分大小写,因此如果用户输入即Yes
或yEs
,{{1 }}将返回playAgain.equals("yes")
<强>更新强>
正如Maroun Maroun所说,最好使用
false
和
"yes".equals(playAgain)
因为如果playAgain为"no".equals(playAgain)
,则不会抛出null
答案 2 :(得分:3)
问题可能是这一行
if (playAgain == "yes")
(之后的那个没有)。
Java中的字符串是对象。这意味着两个字符串可能具有相同的内容,即包含相同的文本,但就==
而言仍然不是“相同”。要比较两个字符串并查看它们是否包含相同的文本,请使用:
if (playAgain.equals("yes"))
答案 3 :(得分:1)
问题在于String
比较的方式。
playAgain == "yes"
,此检查将检查对象是否相等。
但是在这种情况下,需要比较对象的值,以下代码将适合您。
playAgain.equals("yes")
答案 4 :(得分:0)
您需要使用String.equals()
方法而不是==
equals
方法比较字符串的值,==
检查两个对象是否引用同一个对象。