我实例化了我班级的按钮:
linkBtn = new LinkButton(
new URI("http://www.example.com"),
"Click me");
单击它时没有任何反应,所以我想添加一个像这样的动作监听器:
linkBtn.addActionListener(SOMETHING);
我尝试过这样的事情:
linkBtn.addActionListener(new LinkButton.OpenUrlAction());
这会产生以下错误:
包含LinkButton.OpenUrlAction的封闭实例 需要
我还没找到合适的语法。
这是我的类,它扩展了JButton:
import java.awt.Desktop;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.io.IOException;
import java.net.URI;
import javax.swing.JButton;
public class LinkButton extends JButton
implements ActionListener {
/** The target or href of this link. */
private URI target;
final static private String defaultText = "<HTML>Click the <FONT color=\"#000099\"><U>link</U></FONT>"
+ " to go to the website.</HTML>";
public LinkButton(URI target, String text) {
super(text);
this.target = target;
//this.setText(text);
this.setToolTipText(target.toString());
}
public LinkButton(URI target) {
this( target, target.toString() );
}
public void actionPerformed(ActionEvent e) {
open(target);
}
class OpenUrlAction implements ActionListener {
@Override public void actionPerformed(ActionEvent e) {
open(target);
}
}
private static void open(URI uri) {
if (Desktop.isDesktopSupported()) {
try {
Desktop.getDesktop().browse(uri);
} catch (IOException e) { /* TODO: error handling */ }
} else { /* TODO: error handling */ }
}
}
答案 0 :(得分:2)
我不明白为什么你扩展JButton
但你可以在构造函数中默认添加这个监听器。
public LinkButton(URI target, String text) {
super(text);
this.target = target;
//this.setText(text);
this.setToolTipText(target.toString());
this.addActionListener(this);
//this.addActionListener(new OpenUrlAction());
}
或者你可以这样做。
linkBtn.addActionListener(linkBtn.new OpenUrlAction());
outerObject.new InnerClass()
或者您可以使用constructor injection
class OpenUrlAction implements ActionListener{
private URI target;
OpenUrlAction(URI target){
this.target=target;
}
@Override
public void actionPerformed(ActionEvent evt){
open(this.target);
}
}
在客户代码中:
`linkBtn.addActionListener(linkBtn.new OpenUrlAction(lninkBtn.getTarget)); // or the target that you want`
答案 1 :(得分:2)
你可以这样做:
linkBtn.addActionListener(linkBtn.new OpenUrlAction());
但是你的程序结构让我很畏缩。我自己试图让Actions与视图分开。我也更喜欢通过组合而不是继承来扩展。
答案 2 :(得分:2)
我愿意接受建议。我不喜欢我的程序结构...
到目前为止提供的答案都非常出色。
Hovercraft建议使用Action
s,这只是代码的结构。
例如......
import java.awt.Desktop;
import java.awt.EventQueue;
import java.awt.GridBagLayout;
import java.awt.event.ActionEvent;
import java.io.IOException;
import java.net.MalformedURLException;
import java.net.URISyntaxException;
import java.net.URL;
import java.util.logging.Level;
import java.util.logging.Logger;
import javax.swing.AbstractAction;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.UIManager;
import javax.swing.UnsupportedLookAndFeelException;
public class LinkButtonExample {
public static void main(String[] args) {
new LinkButtonExample();
}
public LinkButtonExample() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException | InstantiationException | IllegalAccessException | UnsupportedLookAndFeelException ex) {
}
JFrame frame = new JFrame("Testing");
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setLayout(new GridBagLayout());
frame.add(new JButton(new OpenURLAction(new URL("http://stackoverflow.com/"))));
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
} catch (MalformedURLException ex) {
ex.printStackTrace();
}
}
});
}
public class OpenURLAction extends AbstractAction {
private URL url;
public OpenURLAction(URL url) {
this("<HTML>Click the <FONT color=\\\"#000099\\\"><U>link</U></FONT> to go to the website.</HTML>", url);
}
public OpenURLAction(String text, URL url) {
putValue(NAME, text);
setURL(url);
}
public void setURL(URL url) {
this.url = url;
setEnabled(
url != null
&& Desktop.isDesktopSupported()
&& Desktop.getDesktop().isSupported(Desktop.Action.BROWSE));
putValue(SHORT_DESCRIPTION, url == null ? null : url.toString());
}
public URL getURL() {
return url;
}
@Override
public void actionPerformed(ActionEvent e) {
if (isEnabled()) {
URL url = getURL();
if (url != null && Desktop.isDesktopSupported()
&& Desktop.getDesktop().isSupported(Desktop.Action.BROWSE)) {
try {
Desktop.getDesktop().browse(url.toURI());
} catch ( IOException | URISyntaxException ex) {
ex.printStackTrace();
}
}
}
}
}
}
查看How to use Actions了解详情
答案 3 :(得分:0)
到目前为止,我提出了这个问题。我将此方法添加到我的LinkButton类:
public void init() {
this.addActionListener(this);
}
然后我添加了这段代码来添加动作监听器:
linkBtnDonate.init();
它正在运作。我愿意接受其他建议。