如何使用移动平均线平滑mathematica中的histogram3D?

时间:2013-06-21 22:35:26

标签: 3d wolfram-mathematica histogram smoothing moving-average

我正在尝试使用mathematica中的移动平均来平滑3D直方图。我知道有一个名为smoothhistogram3D的函数,它接近我想要的,但是,它似乎只能选择使用分布函数来平滑曲线。通过修改this stackoverflow answer以包含interpolationOrder和移动平均特征,我能够创建一个平滑2D直方图的函数。

MovAvgHistoPlot[MovAvg_, dx_] := Module[{histList, transposedHistList, histListAvg},
  histList = HistogramList[data, {dx}];

  transposedHistList = Transpose[{histList[[1]],ArrayPad[histList[[2]], {0, 1}, 
    "Fixed"]}];
  histListAvg = MovingAverage[transposedHistList, MovAvg];
  histPlot = ListPlot[histListAvg, InterpolationOrder -> 3, Joined -> True, 
    AxesOrigin -> {histListAvg[[1, 1]], 0}, PlotRange -> All, InterpolationOrder -> 3,
    PlotStyle -> Black, FrameLabel -> {"kTh", "Ion Intensity"},Frame -> {{True, False}, 
    {True, False}}, Axes -> False, ImageSize -> Large]
]

Manipulate[MovAvgHistoPlot[MovAvg, dx], {{MovAvg, 1, "Moving Average"}, 1, 500, 1}, 
  ContinuousAction -> False]

我尝试使用下面的代码将其扩展到第三维,但没有成功。

MovAvgHistPlot3D[MovAvg_] := Module[{HistList3D, XAndZGroupedValues, XValues, ZValues, 
  XAndZValues, YValues, ListPlot3DPoints},

  HistList3D = HistogramList[data];
  XAndZValues = Flatten[Partition[Table[Riffle[HistList3D[[1, 2]], 
    HistList3D[[1, 1, i]], {1, -1, 2}], {i,Length[HistList3D[[1, 1]]]}], {1, 2}]];
  YValues = Flatten[ArrayPad[Map[ArrayPad[##, {0, 1}, "Fixed"] &, HistList3D[[2]]], 
    {0, 1}, "Fixed"]]; 
  ListPlot3DPoints = Partition[Riffle[XAndZValues, YValues, {3, -1, 3}], 3];
  ListPlot3DPointsAvg = MovingAverage[ListPlot3DPoints, MovAvg];
  ListPlot3D[ListPlot3DPointsAvg, InterpolationOrder -> 3, Joined -> True]
  ]

Manipulate[MovAvgHistPlot3D[MovAvg], {{MovAvg, 1, "Moving Average"}, 1, 1000, 1},
  ContinuousAction -> False]

但是,3D功能使用我的数据集输出此图像:http://imgur.com/MJeBbwW

我尝试使用与此类似的方法,除了可以选择使用移动平均线来平滑它:

ListPlot3D[HistogramList[filteredData1]]

然而,它输出了这样的图像:

http://imgur.com/Bkj0R9W
(Sorry, can't post more than two links due to lack of reputation points)

我想要的数据集与smoothhistogram3D的输出非常相似,但可以选择平滑移动平均线。

http://imgur.com/NRj6V2R

有什么建议吗?有没有更简单的方法我没有意识到?

很抱歉,我意识到代码,尤其是第二部分,几乎无法读取。我是mathematica的新手,只是想让它发挥作用。

这也是我第一次发布堆栈溢出,请原谅任何格式或指南错误。

0 个答案:

没有答案