我的PDO有问题...
我有错误的类,用于执行select(以及将来 - 其他)查询到数据库,使用PHP:PDO ......就像那样:
$db = new PDOAct;
$arr = array("from" => "users");
$row = array("id");
$val = array(0);
$type = array("INT");
$db->select($arr, $row, $val, $type);
当我执行此操作时,
<? if (!defined("sKEY")) { exit("Houston, We've Got a Problem"); }
class PDOAct
{
public $db;
function __construct()
{
try {
$this->db = new PDO(DBdriver.':host='.DBhost.';dbname='.DBbase, DBuser, DBpass);
$this->db->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION );
} catch(PDOException $e) {
$this->err($e->getMessage());
}
}
function select($arr, $row, $val, $type)
{
try {
for ($i=0; $i<count($row); $i++)
{
if (isset($row[$i]) && isset($val[$i]) && isset($type[$i]))
{
if ($arr[select] != "" && $arr[select] != "*")
{
if ($i < 1)
{
$do = $this->db->prepare("SELECT `".$arr[select]."` FROM `".$arr[from]."` WHERE `".$row[$i]."` = ':".$row[$i]."'");
} else {
$do = $do.$this->db->prepare(" AND `".$row[$i]."` = ':".$row[$i]."'");
}
} elseif ($arr[select] == "" || $arr[select] == "*") {
if ($i < 1)
{
$do = $this->db->prepare("SELECT * FROM `".$arr[from]."` WHERE `".$row[$i]."` = ':".$row[$i]."'");
} else {
$do = $do.$this->db->prepare(" AND `".$row[$i]."` = ':".$row[$i]."'");
}
}
$do->bindValue(':'.$row[$i], $val[$i], "PDO::PARAM_".$type[$i]);
} elseif (!isset($row[$i]) && !isset($val[$i]) && !isset($type[$i])) {
if ($arr[select] != "" && $arr[select] != "*" && $i == 0)
{
$do = $this->db->prepare("SELECT `".$arr[select]."` FROM `".$arr[from]."`");
} elseif ($arr[select] == "" || $arr[select] == "*" && $i == 0) {
$do = $this->db->prepare("SELECT * FROM `".$arr[from]."`");
}
} else {
exit("Query error!");
}
}
var_dump($this->db->prepare("SELECT * FROM `".$arr[from]."` WHERE `".$row[0]."` = ':".$row[0]."'"));
} catch(PDOException $e) {
$this->err($e->getMessage());
}
return $do;
}
function err($e)
{
file_put_contents('log'.DIR_SEP.'PDOerrors.txt', $e."\n", FILE_APPEND);
exit("Houston, We've Got a Problem");
}
}
?>
它给了我一个php错误:“在非对象上调用成员函数execute()”
我试图使用var_dump();
- 它给我这样的smth:
object(PDOStatement)#4 (1) { ["queryString"]=> string(40) "SELECT * FROM `users` WHERE `id` = ':id'" }
所以$ this-&gt; db-&gt; prepare()确定。 有什么问题?我在3个多小时内受苦... 谢谢!
答案 0 :(得分:0)
你不能做这样的事情:
if ($i < 1)
{
$do = $this->db->prepare("SELECT * FROM `".$arr[from]."` WHERE `".$row[$i]."` = ':".$row[$i]."'");
} else {
$do = $do.$this->db->prepare(" AND `".$row[$i]."` = ':".$row[$i]."'");
}
你需要生成你的sql语句(动态),只有当你准备好完整的语句时,prepare
它才能连接并准备部分语句。
答案 1 :(得分:0)
您正在对非对象调用execute,请确保使用正确的顺序
$data = array("id" => "your_row_id");
$STH = $this->db->prepare($your_query); // In which you are using your :id named placeholder
$STH->execute($data);