Question

我正在使用以下代码从SQL表中检索列 -

MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.ID ELSE NULL END) "MondayHourlyAM",                 
            MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN s.SchoolName ELSE NULL END) "MondayHourlyAMSchoolName",
            MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN REPLACE(REPLACE(LTRIM(RIGHT(CONVERT(VARCHAR, bd.StartTime, 100), 7)) + '-' + LTRIM(RIGHT(CONVERT(VARCHAR(20), bd.EndTime, 100), 7)), 'AM',''), 'PM', '') ELSE NULL END) "MondayHourlyAMTimes",
            MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.TotalChargeAmount ELSE NULL END) "MondayHourlyAMTotalChargeAmount",
            MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.TotalPayAmount ELSE NULL END) "MondayHourlyAMTotalPayAmount",
            MAX(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.BandBookedAt ELSE NULL END) "MondayHourlyAMBandBookedAt",

            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.ID ELSE NULL END) "MondayHourlyAM2",                    
            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN s.SchoolName ELSE NULL END) "MondayHourlyAM2SchoolName",
            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN REPLACE(REPLACE(LTRIM(RIGHT(CONVERT(VARCHAR, bd.StartTime, 100), 7)) + '-' + LTRIM(RIGHT(CONVERT(VARCHAR(20), bd.EndTime, 100), 7)), 'AM',''), 'PM', '') ELSE NULL END) "MondayHourlyAM2Times",
            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.TotalChargeAmount ELSE NULL END) "MondayHourlyAM2TotalChargeAmount",
            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.TotalPayAmount ELSE NULL END) "MondayHourlyAM2TotalPayAmount",
            MIN(CASE WHEN bd.DayText = 'Monday' and bd.BookingDuration = 3 and CONVERT(time(0), bd.StartTime) < CONVERT(time(0), '12:00:00') AND bd.NoOfHOurs < 5.5 and s.PrimarySchool = 1 THEN bd.BandBookedAt ELSE NULL END) "MondayHourlyAM2BandBookedAt",

当此代码运行时，我会收到2次预订，但是返回的费用/支付费用是针对其他预订的。即 -

应该是预订1-收费20英镑，支付10英镑预订2-收费100英镑，支付50英镑

但是我得到了预订1 - 收费100英镑，支付50英镑预订2 - 收费20英镑，支付10英镑

我认为这是因为它使用MAX和MIN返回最高和最低的im。如何将返回到“HourlyAM”列的MAX和MIN值关联起来？

希望我解释得很好！感谢

Answer 1

如果不更好地了解您的数据，我不会尝试涉及您的标准，但我认为您最好使用ROW_NUMBER（）：

SELECT *
FROM ( SELECT *, ROW_NUMBER() OVER (ORDER BY MondayHourlyAMTimes DESC) 'Booking1'
               , ROW_NUMBER() OVER (ORDER BY MondayHourlyAMTimes ) 'Booking2'
       FROM Table
       WHERE common criteria
     )
WHERE Booking1 = 1 OR Booking2 = 1

这里的想法是，您根据一个字段为符合条件的每一行分配排名，然后根据该排名返回完整行。

SELECT CASE中的SQL MIN和MAX关系

1 个答案: