Question

我正在尝试使用python与NTLK来获得许多单词的缩略语（现在为2）。似乎我可以让它与第一个单词一起使用，但不是第二个单词。我猜我还有很多东西要学习NTLK。下面有一些简化的示例代码。我基本上试图获得两个缩略语列表，每个单词列表1个。第一个for循环一切顺利。在我尝试了第二个字后，我得到了：

syn2 = wn.synsets(word)[0].lemmas[y]
IndexError: list index out of range

希望有人能帮助我理解为什么会这样。

import nltk
from nltk.corpus import wordnet as wn
import string
from array import * 

syn1 = '' 
syn2 = '' 
mylist = []    
mylist2 = []    
mylist3 = []  


Web_Keywd = 'car loan'
wuser_words = Web_Keywd.split()   

for word in wuser_words:                           


     i=i+1
     #first
     if (i == 1) :
         synset1 = wn.synsets(word)    
         y = 0     
         for synset in synset1:
             syn1 = wn.synsets(word)[0].lemmas[y]
             syn1 = syn1.name
             mylist2.append(syn1)
             y=y+1
     if (i == 2) :
         y = 0     
         for synset2 in wn.synsets(word):
             syn2 = wn.synsets(word)[0].lemmas[y]
             syn2 = syn2.name
             mylist3.append(syn2)
             y=y+1

Answer 1

我可能在使用wn.synsets(word)[0].lemmas[y]之前的回答中误导了你。你需要明确地循环遍历lemmas，因为你不知道有多少提前。用例示例：

Web_Keywd = 'car loan cheap'

results = {}
for word in Web_Keywd.split():
    for synset in wn.synsets(word):
        for lemma in synset.lemmas:
            results.setdefault(word, []).append(lemma.name)

results现在看起来如下：

{'car': ['car', 'auto', 'automobile', 'machine'...],
'loan': ['loan', 'loanword', 'loan', 'lend', 'loan'...],
'cheap': ['cheap', 'inexpensive', 'brassy', 'cheap...]}

为每个提交的字词获取唯一的结果，与其他字词无关：

.... # same as above
            results.setdefault(word, set()).add(lemma.name)

获取所有提交单词的唯一字词列表：

Web_Keywd = 'car loan cheap'

words = set(Web_Keywd.split())
results = set(
    lemma.name
    for word in words
        for synset in wn.synsets(word)
            for lemma in synset.lemmas
)
# results -> {'loanword', 'tatty', 'automobile', 'cheap', 'chinchy',...

正确使用NLTK与python

1 个答案: