Question

我们可以使用dom解析器在xml文件中按id搜索元素，例如：

<root>
  <context id="one">
    <entity>
      <identifier>new one</identifier>
    </entity>
  </context>

  <context id="two">
    <entity>
      <identifier>second one</identifier>
    </entity>
  </context>

</root>

我想要一个id =“one”的节点，我的代码

DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder();
Document document = docBuilder.parse(new File("filename.xml"));

Element ele = document.getElementById("one");

返回null，

还有其他方法吗？

Answer 1

来自Document.getElementById

的文档

Note: Attributes with the name "ID" or "id" are not of type ID unless so defined.

问题是Document不知道名为id的属性是标识符，除非你告诉它。在致电DocumentBuilderFactory之前，您需要在newDocumentBuilder上设置架构。这样DocumentBuilder就会知道元素类型。

在架构中，您需要在适当的位置使用以下内容：

<xs:attribute name="id" type="xs:ID"/>

Answer 2

您可以使用JDK / JRE中的javax.xml.xpath API通过XPath查找元素。

示例

import java.io.File; import javax.xml.parsers.*; import javax.xml.xpath.*; import org.w3c.dom.*; public class Demo { public static void main(String[] args) throws Exception { DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder(); Document document = docBuilder.parse(new File("filename.xml")); XPathFactory xpathFactory = XPathFactory.newInstance(); XPath xpath = xpathFactory.newXPath(); Element element = (Element) xpath.evaluate("//*[@id='one']", document, XPathConstants.NODE); } }

Answer 3

您可以使用像Jsoup这样的第三方库来完成这项工作。

File input = new File("/tmp/input.xml");
Document doc = Jsoup.parse(input, "UTF-8", "test");

然后你可以使用这样的东西：

doc.select("context#id=one")

这会回答你的问题吗？

Answer 4

尝试使用XML - Xpath表达式非常容易

File fXmlFile = new File("filePath");
DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
Document doc = dBuilder.parse(fXmlFile);


doc.getDocumentElement().normalize();
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());


XPathFactory factory = XPathFactory.newInstance();

            XPath xpath = factory.newXPath();

            String expression;
            Node node;

            // 1. elements with id '1'
            expression = "//context[@id='one']"; 
            node = (Node ) xpath.evaluate(expression, doc, XPathConstants.NODE);

xml按id搜索元素

4 个答案: