嘿伙计们我一直在尝试编写代码,我从PHP订单页面提交表单,以便它可以使用所需信息更新MySQL数据库
我在这里订购了PHP代码:
<form action="http://zim.cs.uow.edu.au/~ga420/order.php" method="post">
<tr>
<th>Shirts</th>
<th>Quantity</th>
</tr>
<tr>
<td>
<br />
<input type="checkbox" name="items" value="SH01" />
<label for="rd1">Obey T-Shirt: $9.99</label>
</div>
<br />
<input type="checkbox" name="items" value="SH02" />
<label for="rd1">Obey Professor: $9.99</label>
</div>
<br />
<input type="checkbox" name="items" value="SH03" />
<label for="rd1">Hustle T-Shirt: $9.99</label>
</div>
<br />
<input type="checkbox" name="items" value="SH04" />
<label for="rd1">Hip-Hop Support: $9.99</label>
</div>
<br />
<input type="checkbox" name="items" value="SH05" />
<label for="rd1">90's Shirt: $9.99</label>
</div>
<br />
<input type="checkbox" name="items" value="SH06" />
<label for="rd1">DOPE Shirt: $9.99</label>
</div>
<br />
<br />
</td>
<td>
<br />
<input type="text" name="qty" size="2" />
<br/>
<input type="text" name="qty" size="2" />
<br/>
<input type="text" name="qty" size="2" />
<br/>
<input type="text" name="qty" size="2" />
<br/>
<input type="text" name="qty" size="2" />
<br/>
<input type="text" name="qty" size="2" />
<br/>
<br />
</td>
</tr>
<tr>
<td>
<br />
<input type="checkbox" name="items[]" value="SO1" />
<label for="rd1">Shoe - Red Lace: $19.99</label>
</div>
<br />
<input type="checkbox" name="items[]" value="SO2" />
<label for="rd1">Shoe - Red High Top: $19.99</label>
</div>
<br />
<input type="checkbox" name="items[]" value="SO3" />
<label for="rd1">Shoe - White: $19.99</label>
</div>
<br />
<input type="checkbox" name="items[]" value="SO4" />
<label for="rd1">Shoe - Black: $19.99</label>
</div>
<br />
<input type="checkbox" name="items[]" value="SO5" />
<label for="rd1">Shoe - Black High Top: $19.99</label>
</div>
<br />
<input type="checkbox" name="items[]" value="SO6" />
<label for="rd1">Red Basketball: $19.99</label>
</div>
<br />
<br />
</td>
<td>
<br />
<input type="text" name="qty[]" size="2" />
<br/>
<input type="text" name="qty[]" size="2" />
<br/>
<input type="text" name="qty[]" size="2" />
<br/>
<input type="text" name="qty[]" size="2" />
<br/>
<input type="text" name="qty[]" size="2" />
<br/>
<input type="text" name="qty[]" size="2" />
<br/>
<br />
</td>
</tr>
<tr>
<td>
<br />
<input type="checkbox" name="items[]" value="SN1" />
<label for="rd1">Snapback Bullets: $29.99</label>
</div>
<br />
<input type="checkbox" name="items[]" value="SN2" />
<label for="rd1">Snapback: $29.99</label>
</div>
<br />
<input type="checkbox" name="items[]" value="SN3" />
<label for="rd1">Snapback Bullets: $29.99</label>
</div>
<br />
<input type="checkbox" name="items[]" value="SN4" />
<label for="rd1">Snapback Bullets: $29.99</label>
</div>
<br />
<input type="checkbox" name="items[]" value="SN5" />
<label for="rd1">Snapback Bullets: $29.99</label>
</div>
<br />
<input type="checkbox" name="items[]" value="SN6" />
<label for="rd1">Snapback Bullets: $29.99</label>
</div>
<br />
<br />
</td>
<td>
<br />
<input type="text" name="qty[]" size="2" />
<br/>
<input type="text" name="qty[]" size="2" />
<br/>
<input type="text" name="qty[]" size="2" />
<br/>
<input type="text" name="qty[]" size="2" />
<br/>
<input type="text" name="qty[]" size="2" />
<br/>
<input type="text" name="qty[]" size="2" />
<br/>
<br />
</td>
</tr>
</tr>
</table>
<br />
<input type="submit" name="submit">
</form>
<?php
if (isset($_POST['submit'])){
$conn = mysql_connect('url','username','password');
if (!$con){
die("Could Not Connect: " . mysql_error());
}
mysql_select_db("db",$conn);
$sql = "INSERT INTO Order_Information(Order_ID,Order_Items,Order_Quantity) VALUES (null,$_POST[items]','$_POST[qty]')";
mysql_query($sql, $con);
mysql_close($con);
}
?>
显然我的用户名和密码我不会显示,但是当我点击提交按钮时它表示它无法连接。
您可以在本网站上亲自试用表格: http://zim.cs.uow.edu.au/~ga420/order.php
为什么说我无法连接时,我已经把正确的细节放在了。
有人可以帮忙吗?这一直在强调我:'(
非常感谢您的帮助!!
答案 0 :(得分:1)
如果您在所有字段中使用相同的名称“qty”,则需要序列化所有输入/数量。如果你没有得到答案,我会在稍后更新我的答案。
您的代码上也有小错误,请注意:
VALUES (null,'$_POST[items]','$_POST[qty]')";
- 您在$ _POST [items]
'
$conn = mysql_connect('zim.cs.uow.edu.au','username','password');
- $ conn with 2“n”
因此,更正的版本将是:
<?php
if (isset($_POST['submit'])){
$con = mysql_connect('url','username','password');
if (!$con){
die("Could Not Connect: " . mysql_error());
}
mysql_select_db("db",$con);
$sql = "INSERT INTO Order_Information(Order_ID,Order_Items,Order_Quantity) VALUES (null,'$_POST[items]','$_POST[qty]')";
mysql_query($sql, $con);
mysql_close($con);
}
?>
答案 1 :(得分:0)
更改为此。你在$ conn和$ con上犯了一些错误。然后,查询中'$_POST[items]','$_POST[qty]'
。
if (isset($_POST['submit'])){
$conn = mysql_connect('url','username','password');
if (!$conn){
die("Could Not Connect: " . mysql_error());
}
mysql_select_db("db",$conn);
$sql = "INSERT INTO Order_Information(Order_ID,Order_Items,Order_Quantity) VALUES (null,'$_POST[items]','$_POST[qty]')";
mysql_query($sql, $conn);
mysql_close($conn);
}
希望这个帮助