Question

我正在尝试从json结果中获取值，该结果是从我的javascript中的REST调用返回的。以下是REST的JSON结果

{
    "self": "http://example.com/rest/api/2/project/MTS/role/10002",
    "name": "Administrators",
    "id": 10002,
    "description": "A project role that represents administrators in a project",
    "actors": [{
        "id": 10803,
        "displayName": "Administrator ",
        "type": "atlassian-user-role-actor",
        "name": "admin",
        "avatarUrl": "/secure/useravatar?size=small&avatarId=10108"
    }, {
        "id": 10590,
        "displayName": "jira-administrators",
        "type": "atlassian-group-role-actor",
        "name": "jira-administrators",
        "avatarUrl": "/secure/useravatar?size=small&avatarId=10123"
    }]
}

从这个结果我只需要获取所有演员的名字有人可以帮我用下面的脚本

function getName()
{
var user;
     $.ajax({
        url: "/rest/api/2/project/MITS/role/10002",
        type: 'get',
        dataType: 'json',
        async: false,
        success: function(data) {
            user = data;
       } 
     });
     return user;
}

以上脚本不正确请帮忙

Answer 1

在成功功能中，使用此

users = []; // you will store the names here
$.each(data.actors, function(i,actor){
    if(actor.type === "atlassian-user-role-actor"){
        users.push(actor.name);
    }
})

在用户中，您将获得演员姓名

如果需要，请将您的JSON粘贴到http://www.jsoneditoronline.org/，您将清楚地看到“数据”对象的内容以及如何访问它。

Answer 2

您可以像data.actors

一样访问actor数组

然后使用$.each或for loop

遍历数组

$.each(data.actors, function(i, val) {
   console.log('Actor name :: ' + val.name)
});

如何从REST调用返回JSON结果返回的特定值

2 个答案: