Question

我正在使用已经工作多年的yt-getuseruploads-script，但突然间它在没有错误消息的情况下中止。它就像这样开始

<?php
error_reporting(E_ERROR | E_WARNING | E_PARSE);
ignore_user_abort(true);

function anmelden_yt($name,$passwort)
{
$yt_source = 'known';  
$yt_api_key = 'key';
$yt = null;    
$authenticationURL= 'https://www.google.com/accounts/ClientLogin';  
$httpClient = Zend_Gdata_ClientLogin::getHttpClient(  
$username = $name,  
$password = $passwort,  
$service = 'youtube',  
$client = null,  
$source = $yt_source, // a short string identifying your application  
$loginToken = null,  
$loginCaptcha = null,  
$authenticationURL); 
abschnitt("Login");
return new Zend_Gdata_YouTube($httpClient, $yt_source, NULL, $yt_api_key); 
}


require_once("Zend/Gdata/ClientLogin.php");  
require_once("Zend/Gdata/HttpClient.php");  
require_once("Zend/Gdata/YouTube.php"); 
require_once("Zend/Gdata/App/MediaFileSource.php");  
require_once("Zend/Gdata/App/HttpException.php");  
require_once('Zend/Uri/Http.php');
require_once 'Zend/Loader.php'; 
Zend_Loader::loadClass('Zend_Gdata_YouTube'); 
Zend_Loader::loadClass('Zend_Gdata_AuthSub');
Zend_Loader::loadClass('Zend_Gdata_ClientLogin'); 

echo "1<br>";  
$yt = anmelden_yt($name,$pass);
echo "2<br>";
$videoFeed = $yt->getUserUploads('Google');
sleep(0.5);
echo "3<br>";


    @ob_flush();
@flush();

?>

问题是，3永远不会被打印，输出是

1
2

所以即使是error_reporting（E_ERROR | E_WARNING | E_PARSE）;我没有得到任何错误消息，除了提到的结果。没有过早的休息或死亡。

Answer 1

你确定这是一个时间限制错误吗？尝试做：

ini_set('display_errors','1');

首先看看是否有错误

$ videoFeed = $ yt-＆gt; getUserUploads使脚本死亡

1 个答案: