我有一个应用程序,允许用户安排将来发生的操作。例如,可以选择日期并安排它在每个月的那一天运行(例如:每个月的15日)。但是,我现在需要允许他们选择一个月的一周和一周。例如,他们需要在每月的第一个星期五运行一个动作。因此我允许选择工作日(星期一,星期二,星期三......)和月中的一周(第1,第2,第3,第4或第5)。
以下是我目前使用的查询:
Declare @nowString varchar(19)
Declare @nowDateString varchar(19)
Declare @now datetime
Declare @lastMinute datetime
Declare @nowDate datetime
Set @nowString = '#currentDateTime#:00'
Set @nowDateString = LEFT(@nowString, 10)
set @now = @nowString
set @nowDate = DATEADD(dd, 0, DATEDIFF(dd, 0, @now))
set @lastMinute = DATEADD(mi, -1, @now)
select *
from message_prepared
where schedule = '1'
and active = '1'
and noaa = '0'
and (
(
schedule_type = 'recurring'
and startdate <= @nowDate
and isnull(enddate, DATEADD(yy, 1, @nowDate)) >= @nowDate
and (
@nowDateString + ' ' + isnull(recurring_start_time_hour, '00') + ':' + isnull(recurring_start_time_min, '00') + ':00' = @now
or @nowDateString + ' ' + isnull(recurring_start_time_hour, '00') + ':' + isnull(recurring_start_time_min, '00') + ':00' = @lastMinute
)
-- Test for different type of recurring
and (
( ltrim(rtrim(recurring)) = 'M' and DATEPART(dd, startdate) = DATEPART(dd, @now) )
or ( ltrim(rtrim(recurring)) = 'W' and DATEPART(dw, startdate) = DATEPART(dw, @now) )
or ltrim(rtrim(recurring)) = 'D'
)
)
or (
schedule_type = 'once'
and startdate = @nowDate
and (
@nowDateString + ' ' + onetime_start_time_hour + ':' + onetime_start_time_min + ':00' = @now
or @nowDateString + ' ' + onetime_start_time_hour + ':' + onetime_start_time_min + ':00' = @lastMinute
)
)
)
and repeat_multiple_times = 0
UNION ALL
SELECT *
FROM MESSAGE_PREPARED
WHERE schedule = '1'
AND active = 1
AND noaa = 0
AND recurring = 'D'
AND repeat_multiple_times = 1
AND startDate IS NOT NULL
AND recurring_start_time_hour IS NOT NULL
AND recurring_start_time_hour < 24
AND recurring_start_time_min IS NOT NULL
AND recurring_start_time_min < 60
AND startdate <= @nowDate
AND ISNULL(enddate, DATEADD(yy, 1, @nowDate)) >= @nowDate
AND
(
CASE WHEN repeat_unit = 'M'
THEN
DATEDIFF(n,
CONVERT(DATETIME,
CAST(DATEPART(yyyy, startDate) AS VARCHAR(4)) + '-' +
CAST(DATEPART(mm, startDate) AS VARCHAR(2)) + '-' +
CAST(DATEPART(dd, startDate) AS VARCHAR(2)) + ' ' +
CAST(recurring_start_time_hour AS VARCHAR(2)) + ':' +
CAST(recurring_start_time_min AS VARCHAR(2)) + ':00', 20),
GETDATE()) % repeat_interval
ELSE
DATEDIFF(n,
CONVERT(DATETIME,
CAST(DATEPART(yyyy, startDate) AS VARCHAR(4)) + '-' +
CAST(DATEPART(mm, startDate) AS VARCHAR(2)) + '-' +
CAST(DATEPART(dd, startDate) AS VARCHAR(2)) + ' ' +
CAST(recurring_start_time_hour AS VARCHAR(2)) + ':' +
CAST(recurring_start_time_min AS VARCHAR(2)) + ':00', 20),
GETDATE()) % (repeat_interval * 60)
END = 0
OR
CASE WHEN repeat_unit = 'M'
THEN
(DATEDIFF(n,
CONVERT(DATETIME,
CAST(DATEPART(yyyy, startDate) AS VARCHAR(4)) + '-' +
CAST(DATEPART(mm, startDate) AS VARCHAR(2)) + '-' +
CAST(DATEPART(dd, startDate) AS VARCHAR(2)) + ' ' +
CAST(recurring_start_time_hour AS VARCHAR(2)) + ':' +
CAST(recurring_start_time_min AS VARCHAR(2)) + ':00', 20),
GETDATE()) - 1) % repeat_interval
ELSE
(DATEDIFF(n,
CONVERT(DATETIME,
CAST(DATEPART(yyyy, startDate) AS VARCHAR(4)) + '-' +
CAST(DATEPART(mm, startDate) AS VARCHAR(2)) + '-' +
CAST(DATEPART(dd, startDate) AS VARCHAR(2)) + ' ' +
CAST(recurring_start_time_hour AS VARCHAR(2)) + ':' +
CAST(recurring_start_time_min AS VARCHAR(2)) + ':00', 20),
GETDATE()) - 1) % (repeat_interval * 60)
END = 0
)
仅当reocurring设置为“M”时才会发生这种情况,我想确定今天是一周中的特定日期,一周中的一周还是一小时/分钟。
答案 0 :(得分:2)
这是非常简单的逻辑。今天是下个月的第n个DOW:
因此,本月的第一个星期一总是在1日到7日之间,依此类推。以下是一个示例case
语句来测试它:
declare @DayOfWeek varchar(255) = 'Thursday';
declare @Which int = 3;
select (case when datename(dw, Today) = @DayOfWeek and
(DAY(Today) - 1) / 7 = @Which - 1
then 1
else 0
end)
from (select CAST(getdate() as date) as Today) t
我以这种方式构建了查询,因此您可以使用不同的值对其进行测试。只需使用Today
或getdate() - 3
替换定义'2013-01-01'
的表达式。