Question

在试图弄清楚如何将.NET System.ServiceModel.Channels.Message对象转换为XmlDocument时，我想我可以这样做：

Message message = Message.CreateMessage(messageVersion, "SOAPAction");

using(var messageBuffer = message.CreateBufferedCopy(int.MaxValue))
{
    var stream = new MemoryStream();
    using(var xmlWriter = XmlWriter.Create(stream))
    {
        var xmlDocument = new XmlDocument();

        messageBuffer.WriteMessage(stream);
        stream.Flush();

        stream.Position = 0;
        xmlDocument.Load(stream);
        stream.Close();

        Debug.Writeline(xmlDocument.OuterXml);
    }
}

但是，这会导致xmlDocument.Load（stream）出错：

"Data at the root level is invalid. Line 1, position 1."

我现在意识到我应该将Message对象的WriteMessage与XmlWriter对象结合使用，如下所示：

Message message = Message.CreateMessage(messageVersion, "SOAPAction");
using(var messageBuffer = message.CreateBufferedCopy(int.MaxValue))
{
    var stream = new MemoryStream();
    using(var xmlWriter = XmlWriter.Create(stream))
    {
        var xmlDocument = new XmlDocument();

        messageBuffer.CreateMessage().WriteMessage(xmlWriter);
        xmlWriter.Flush();
        stream.Flush();

        stream.Position = 0;
        xmlDocument.Load(stream);

        xmlWriter.Close();
        stream.Close();

        Debug.WriteLine(xmlDocument.OuterXml);
    }
}

我确定我缺少一些基本观点，但这引出了我的问题 - MessageBuffer对象上的WriteMessage（Stream流）有什么用处？

如何在.NET WCF中使用MessageBuffer对象的WriteMessage（Stream stream）方法？

0 个答案: