Question

我有一个脚本，它有两个苹果脚本，可以打开一个新标签并执行命令。我希望第二个苹果脚本等到第一个苹果脚本的命令行动作完成。在继续之前，我宁愿不必长时间睡一觉。

我有办法做到这一点吗？

这就是我所拥有的：

 osascript -e 'tell application "Terminal" to activate' \
 -e 'tell application "System Events" to tell process "Terminal" to keystroke "t" using command down' \
 -e 'tell application "Terminal" to do script "cd '$current_dir'" in selected tab of the front window' \
 -e 'tell application "Terminal" to do script "./my_script arg1" in selected tab of the front window'

 ------ Wait until this process is finished -------

 osascript -e 'tell application "Terminal" to activate' \
 -e 'tell application "System Events" to tell process "Terminal" to keystroke "t" using command down' \
 -e 'tell application "Terminal" to do script "cd '$current_dir'" in selected tab of the front window' \
 -e 'tell application "Terminal" to do script "./my_script different_arg1" in selected tab of the front window'

Answer 1

您可以检查窗口或标签的繁忙属性：

tell application "Terminal"
    set w to do script "sleep 1"
    repeat
        delay 0.1
        if not busy of w then exit repeat
    end repeat
end tell

osascript -e 'on run {a}
    tell application "Terminal"
        activate
        tell application "System Events" to keystroke "t" using command down
        do script "cd " & quoted form of a & "; sleep 1" in window 1
        repeat
            delay 0.1
            if not busy of window 1 then exit repeat
        end repeat
        tell application "System Events" to keystroke "t" using command down
        do script "cd " & quoted form of a & "; sleep 1" in window 1
    end tell
end run' /tmp

让脚本等到最后一个脚本完成

1 个答案: