我想使用lucene实现类似于IDE中的“在文件中查找”。基本上想要搜索.c,.cpp,.h,.cs和.xml等源代码文件。我尝试了apache网站上显示的演示。它返回没有行号和该文件中出现次数的文件列表。我相信应该有一些方法来实现它。
有没有获得这些细节?
答案 0 :(得分:1)
您能否分享一下apache网站上显示的演示链接?
在这里,我将向您展示如何在一组文档中获得术语的术语频率:
public static void main(final String[] args) throws CorruptIndexException,
LockObtainFailedException, IOException {
// Create the index
final Directory directory = new RAMDirectory();
final Analyzer analyzer = new StandardAnalyzer(Version.LUCENE_36);
final IndexWriterConfig config = new IndexWriterConfig(
Version.LUCENE_36, analyzer);
final IndexWriter writer = new IndexWriter(directory, config);
// addDoc(writer, field, text);
addDoc(writer, "title", "foo");
addDoc(writer, "title", "buz qux");
addDoc(writer, "title", "foo foo bar");
// Search
final IndexReader reader = IndexReader.open(writer, false);
final IndexSearcher searcher = new IndexSearcher(reader);
final Term term = new Term("title", "foo");
final Query query = new TermQuery(term);
System.out.println("Query: " + query.toString() + "\n");
final int limitShow = 3;
final TopDocs td = searcher.search(query, limitShow);
final ScoreDoc[] hits = td.scoreDocs;
// Take IDs and frequencies
final int[] docIDs = new int[td.totalHits];
for (int i = 0; i < td.totalHits; i++) {
docIDs[i] = hits[i].doc;
}
final Map<Integer, Integer> id2freq = getFrequencies(reader, term,
docIDs);
// Show results
for (int i = 0; i < td.totalHits; i++) {
final int docNum = hits[i].doc;
final Document doc = searcher.doc(docNum);
System.out.println("\tposition " + i);
System.out.println("Title: " + doc.get("title"));
final int freq = id2freq.get(docNum);
System.out.println("Occurrences of \"" + term.text() + "\" in \""
+ term.field() + "\" = " + freq);
System.out.println("--------------------------------\n");
}
searcher.close();
reader.close();
writer.close();
}
这里我们将文档添加到索引中:
private static void addDoc(final IndexWriter w, final String field,
final String text) throws CorruptIndexException, IOException {
final Document doc = new Document();
doc.add(new Field(field, text, Field.Store.YES, Field.Index.ANALYZED));
doc.add(new Field(field, text, Field.Store.YES, Field.Index.ANALYZED));
w.addDocument(doc);
}
这是如何在doc中获取术语的出现次数的示例:
public static Map<Integer, Integer> getFrequencies(
final IndexReader reader, final Term term, final int[] docIDs)
throws CorruptIndexException, IOException {
final Map<Integer, Integer> id2freq = new HashMap<Integer, Integer>();
final TermDocs tds = reader.termDocs(term);
if (tds != null) {
for (final int docID : docIDs) {
// Skip to the next docID
tds.skipTo(docID);
// Get its term frequency
id2freq.put(docID, tds.freq());
}
}
return id2freq;
}
如果将所有内容放在一起并运行它,您将获得此输出:
Query: title:foo
position 0
Title: foo
Occurrences of "foo" in "title" = 2
--------------------------------
position 1
Title: foo foo bar
Occurrences of "foo" in "title" = 4
--------------------------------
答案 1 :(得分:0)
我试了很多论坛,回复是零。所以最后我从@Luca Mastrostefano得到了一个想法,以获得行号详细信息。
lucene searcher的Taginfo返回文件名。我认为这足以获得行号。 Lucene索引不存储实际内容,它实际上存储了哈希值。因此无法直接获取行号。因此,我假设唯一的方法是使用该路径并读取文件并获取行号。
public static void PrintLines(string filepath,string key)
{
int counter = 1;
string line;
// Read the file and display it line by line.
System.IO.StreamReader file = new System.IO.StreamReader(filepath);
while ((line = file.ReadLine()) != null)
{
if (line.Contains(key))
{
Console.WriteLine("\t"+counter.ToString() + ": " + line);
}
counter++;
}
file.Close();
}
在来自lucene搜索者的路径后调用此函数。