我正在尝试使用jQueryUI选项卡和菜单小部件创建目录列表。我有以下代码来获取目录。
<?php
$db = new PDO('mysql:host='.$host.';dbname='.$databaseName,
$user,
$password,
array(
PDO::ATTR_EMULATE_PREPARES => false,
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION
)
);
$menu = '';
$charTabs = '<div id="charTabs">'; //1
$db->exec('set names utf8');
$queryFirstLetters = $db->prepare('SELECT DISTINCT LEFT(organization, 1) as org FROM Organizations WHERE parent_id = 0 ORDER BY organization', array(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY => true));
//Add each first characters to the charTabs
$queryFirstLetters->execute();
$charTabs .='<ul>'; //2
while($rowFL = $queryFirstLetters->fetch(PDO::FETCH_ASSOC))
{
$charTabs .= '<li><a href="#' . $rowFL['org'] . '">' . $rowFL['b'] . '</a></li>';//3
}
$charTabs .= '</ul>'; //4
//Create Divs corresponding to list items for each first letter.
$queryFirstLetters->execute();
while($rowFL = $queryFirstLetters->fetch(PDO::FETCH_ASSOC))
{
$charTabs .= '<div id="' . $rowFL['org'] . '">'; //5
//Get the parent organizations and add their children as sub menu items
$queryParentOrganizations = $db->prepare('SELECT * FROM Organizations WHERE parent_id = 0 AND LEFT(organization,1) = :p1 ORDER BY organization', array(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY => true));
$queryParentOrganizations->bindValue(':p1', $rowFL['org'], PDO::PARAM_STR);
//This is the line 26 which crashes
$queryParentOrganizations->execute();
//This is the line 26 which crashes
echo '<script>$(function(){ $("#menu'.$rowFL['org'].'").menu(); });</script>';
$menu = '<ul id="menu'.$rowFL['org'].'">';
while($rowPO = $queryParentOrganizations->fetch(PDO::FETCH_ASSOC))
{
$queryChildOrganizations = $db->prepare('SELECT * FROM Organizations WHERE parent_id = :p1 ORDER BY organization', array(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY => true));
$queryChildOrganizations->bindValue(':p1', $rowPO['id'], PDO::PARAM_INT);
$queryChildOrganizations->execute();
$menu .= '<li><a class="list" href="#">'.$rowPO['organization'].'</a>';
if ($queryChildOrganizations->rowCount() > 0 )
{
$menu .= '<ul>';
while($rowCO = $queryChildOrganizations->fetch(PDO::FETCH_ASSOC))
{
$menu .= '<li><a class="list" href="#' . $rowCO['id'] . '">' . $rowCO['organization'] . '</a></li>';
}
$menu .= '</ul>';
}
else
{
$menu .= '</li>';
}
}
$menu .= '</ul>';
$charTabs .= $menu . '</div>';
}
$charTabs .= '</div>';
echo $charTabs;
?>
忽略性能测试,它可以正常工作。但在上传到服务器后,我收到了与PDO相关的以下错误。
PHP致命错误:带有消息的未捕获异常'PDOException' 'SQLSTATE [HY000]:常规错误:2014无法执行查询 其他未缓冲的查询处于活动状态。考虑使用 PDOStatement对象::使用fetchall()。或者,如果您的代码只是永远 要对mysql运行,您可以通过设置启用查询缓冲 PDO :: MYSQL_ATTR_USE_BUFFERED_QUERY属性。'在 /home/server/public_html/directory/index.php:26
堆栈追踪:
#
0 /home/server/public_html/directory/index.php(26):PDO-&gt; prepare('SELECT * FROM O ...')第26行/home/server/public_html/directory/index.php中
#
1 /home/server/public_html/directory/index.php(26):include('/ home / server / publ ...')
#
2 {main}
答案 0 :(得分:0)
当其他未缓冲的查询处于活动状态时,无法执行查询。考虑使用PDOStatement::fetchAll()
。或者,如果您的代码只是针对mysql运行,则可以通过设置PDO::MYSQL_ATTR_USE_BUFFERED_QUERY
属性来启用查询缓冲。