Question

给出一个像这样的字符串数组的数组：

incoming = [["1","A","C","3"],
            ["2","A","C","1"],
            ["1","B","D","3"],
            ["2","B","D","4"],
            ["2","B","D","5"]];

如何将其转换为像这样的json对象：

[
  { "1": [
         { "A": [
                 { "C": ["3"] 
                 }
              ]
         },
         { "B": [
                 { "D": ["3"] 
                 }
              ]
         }
       ]
   },
   { "2": [
         { "A": [
                 { "C": ["1"] 
                 }
              ]
         },
         { "B": [
                 { "D": ["4","5"] 
                 }
              ]
         }
       ]
   }
]

我已经查看了相关问题的几个答案，但无法弄清楚如何将它们映射到这个特定要求。

在PHP中它会很简单。

foreach (incoming AS inc)
{
    output[inc[0]][inc[1]][inc[2]][inc[3]] = "x"; 
}

谢谢！

Answer 1

你的问题制定得不是很好。也许你想要：

var incoming = [['1', 'A', 'C', '3'], ['2', 'A', 'C', '1'], ['1', 'B', 'D', '3'], ['2', 'B', 'D', '4'], ['2', 'B', 'D', '5']];
var obj = {}, propNames = ['prop1', 'prop2', 'prop3', 'prop4', 'prop5'];
for(var i in incoming){
   obj[propNames[i]] = incoming[i];
}

但请注意，您无法使用早期版本的IE在for in或.getElementsByTagName()上运行.getElementsByName()循环。如果您根据代码看起来如此获取信息：

var incoming = [['1', 'A', 'C', '3'], ['2', 'A', 'C', '1'], ['1', 'B', 'D', '3'], ['2', 'B', 'D', '4'], ['2', 'B', 'D', '5']];
var obj = {}, propNames = ['prop1', 'prop2', 'prop3', 'prop4', 'prop5'];
for(var i=0,l=incoming.length; i>l; i++){
    obj[propNames[i]] = incoming[i];
}

请注意，arrayName[increment]或objectName[property]获取的JavaScript值等同于PHP $value中的foreach($whatever as $value)变量。当然，我所做的就是将每个数组分配给obj.prop1，依此类推。它不会创建您显示的结构。这将要求JavaScript对象的每个属性都有不同的名称。

要复制底层PHP代码，在JavaScript中它可能看起来像：

var output = {};
for(var i in incoming){
  var inc = incoming[i];
  output[inc[0]][inc[1]][inc[2]][inc[3]] = 'x';
}

请注意，我上面的最后一段代码，以及您的上一个代码段没有任何意义。这在PHP或JavaScript中不起作用。

Answer 2

将其分解为两个步骤，

步骤1，将数组转换为 Object 树

var incoming = [["1","A","C","3"], ["2","A","C","1"], ["1","B","D","3"],
                ["2","B","D","4"], ["2","B","D","5"]];

var i, j, o = {}, c, k;

for (i = 0; i < incoming.length; ++i) {
    c = o;
    for (j = 0; j < incoming[i].length; ++j) {
        k = incoming[i][j];
        if (!c[k]) c[k] = {};
        c = c[k];
    }
}

现在o看起来像你想要的，除了它没有按照你的意愿排列，所以需要更多的工作。
步骤2，使用递归

，通过keys =＆gt;数组重新创建 Object 树

function recurseKeys(o) {
    var arr = [],
        k = Object.getOwnPropertyNames(o),
        i, c;
    for (i = 0; i < k.length; ++i) {
        if (Object.getOwnPropertyNames(o[k[i]]).length)
            c = {}, c[k[i]] = recurseKeys(o[k[i]]);
        else
            c = k[i];
        arr.push(c);
    }
    return arr;
}

o = recurseKeys(o);

现在o应该具有您想要的结构，所以JSON-ify it

JSON.stringify(o);
// "[{"1":[{"A":[{"C":["3"]}]},{"B":[{"D":["3"]}]}]},{"2":[{"A":[{"C":["1"]}]},{"B":[{"D":["4","5"]}]}]}]"

从字符串数组中创建Javascript树

2 个答案: