Question

我有一个包含UITableView的viewController。这个viewController实现了UITableViewDelegate和UITableViewDataSource，我也试图实现以下方法：

的touchesBegan touchesMoved touchesEnded

但是，这些方法没有被调用。我试图调用这些方法来响应用户触摸UITableView内的UIImageView，但这样做只调用这个方法：

- (void) tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath {


    [self.view bringSubviewToFront:_imageView];

    [UIView animateWithDuration:.3 animations:^{


        CGRect rect = [self.view convertRect:[tableView rectForRowAtIndexPath:indexPath] fromView:tableView];

        CGFloat floatx = _imageView.frame.origin.x - rect.origin.x;
        _imageView.frame = CGRectMake(rect.origin.x + floatx, rect.origin.y, _imageView.frame.size.width, _imageView.frame.size.height);

    }];


    NSLog(@"Table row %d has been tapped", indexPath.row);


}

我希望继续调用此方法，但也可以调用：

    - (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event {

    UITouch *touch = [touches anyObject];

    if ([touch view] == _imageView) {
        //need to make sure user can only move the UIImageView up or down
        CGPoint location = [touch locationInView:_imageView];
        //ensure UIImageView does not move outside UIITableView

        CGPoint pt = [[touches anyObject] locationInView:_imageView];
        CGRect frame = [_imageView frame];
        //Only want to move the UIImageView up or down, not sideways at all

        frame.origin.y += pt.y - _startLocation.y;

        [_imageView setFrame: frame];

        _imageView.center = location;

        return;
    }
}

当用户在UITableView中拖动UIImageView时。

谁能看到我做错了什么？

提前致谢所有回复

的人

Answer 1

除了我试图对UIWebView实施触摸检测外，我遇到了类似的问题。我最终通过向UIWebView的.view属性添加UIPanGestureRecognizer来克服它。

实施此方法：

- (BOOL)gestureRecognizer:(UIGestureRecognizer *)gestureRecognizer shouldRecognizeSimultaneouslyWithGestureRecognizer:(UIGestureRecognizer *)otherGestureRecognizer { return YES; }

然后将UIPanGestureRecognizer添加到UITableView，如下所示：

UIPanGestureRecognizer *panGesture; panGesture = [[UIPanGestureRecognizer alloc] initWithTarget:self action:@selector(panGestureDetected:)]; panGesture.maximumNumberOfTouches = 1; panGesture.minimumNumberOfTouches = 1; panGesture.delegate = self; [self.tableView addGestureRecognizer:panGesture];

然后实现方法

- (void)panGestureDetected:(UIPanGestureRecognizer *)recognizer { }

现在，每次UIPanGestureRecognizer检测到平移手势时，它都会调用该方法，您可以通过调用返回CGPoint的方法[recognizer locationInView:self.tableView.view];来获取UIPanGestureRecognizer的位置。您还可以通过调用返回[recognizer state]的{{1}}来获取UIPanGestureRecognizer的状态。

Answer 2

您是否在视图上设置了userInteractionEnabled，触摸将在哪里？

无法在iOS中的viewController中调用touchesBegan / touchesMoved方法

2 个答案: