Question

你好我有以下功能：

Block* Keywords::parseBlock(TiXmlElement* element)
{
    double x1 = atoi(element->Attribute("left"));
    double y1 = atoi(element->Attribute("top"));
    double x2 = atoi(element->Attribute("right"));
    double y2 = atoi(element->Attribute("bottom"));
    double width  = abs(x2 - x1);
    int bid = atoi(element->Attribute("id"));

    vector<LineElement*> lines;
    for (TiXmlElement* sub = element->FirstChildElement("line"); sub; sub = sub->NextSiblingElement("line"))
        lines.push_back(parseLine(sub));

    return new Block(y2,x2,y1,x1,bid,width, lines);
}///End function parse Block

LineElement* Keywords::parseLine(TiXmlElement* element)
{
    double x1 = atoi(element->Attribute("left"));
    double y1 = atof(element->Attribute("top"));
    double x2 = atoi(element->Attribute("right"));
    double y2 =  atoi(element->Attribute("bottom"));
    int bid = atoi(element->Attribute("id"));

    vector<Element*> words;
    for (TiXmlElement* sub = element->FirstChildElement("word"); sub; sub = sub->NextSiblingElement("word"))
        words.push_back(parseWord(sub));

    return new LineElement(y2,x2,y1,x1,bid,words);
}///End function parse Line

Element * Keywords::parseWord(TiXmlElement* element)
{
    string w =element->Attribute("value");
    double x1 = atoi(element->Attribute("left"));
    double y1 = atoi(element->Attribute("top"));
    double x2 = atoi(element->Attribute("right"));
    double y2 = atoi(element->Attribute("bottom"));
    int bid = atoi(element->Attribute("id"));

    vector<Letter*> chars;

    for (TiXmlElement* sub = element->FirstChildElement("char"); sub; sub = sub->NextSiblingElement("char"))
        chars.push_back(parseChar(sub));

    return new  Element(w,y1, x1, y2,x2,-1,bid,chars);
}///End function parse word

Letter * Keywords::parseChar(TiXmlElement* element)
{
    string w = element->Attribute("value");
    double x1 = atoi(element->Attribute("left"));
    double y1 = atoi(element->Attribute("top"));
    double x2 = atoi(element->Attribute("right"));
    double y2 =  atoi(element->Attribute("bottom"));
    int bid = atoi(element->Attribute("id"));
    return new Letter(w,y1,x1,y2,x2,bid);
}

我认为我有内存泄漏，如何在返回后删除指针？如何使用析构函数释放内存我遇到运行时错误：alloc

Answer 1

最简单的解决方法就像@BalogPal所说的那样，就是停止像Java那样对待C ++。没有理由从任何这些函数返回指针。尝试这样的事情：

Block Keywords::parseBlock(TiXmlElement* element)
{
    double x1 = atoi(element->Attribute("left"));
    double y1 = atoi(element->Attribute("top"));
    double x2 = atoi(element->Attribute("right"));
    double y2 = atoi(element->Attribute("bottom"));
    double width = abs(x2 - x1);
    int bid = atoi(element->Attribute("id"));

    vector<LineElement> lines;
    for (TiXmlElement* sub = element->FirstChildElement("line"); sub; sub = sub->NextSiblingElement("line"))
        lines.push_back(parseLine(sub));

    return Block(y2, x2, y1, x1, bid, width, lines);
}

LineElement Keywords::parseLine(TiXmlElement* element)
{
    double x1 = atoi(element->Attribute("left"));
    double y1 = atof(element->Attribute("top"));
    double x2 = atoi(element->Attribute("right"));
    double y2 = atoi(element->Attribute("bottom"));
    int bid = atoi(element->Attribute("id"));

    vector<Element> words;
    for (TiXmlElement* sub = element->FirstChildElement("word"); sub; sub = sub->NextSiblingElement("word"))
        words.push_back(parseWord(sub));

    return LineElement(y2, x2, y1, x1, bid, words);
}

Element Keywords::parseWord(TiXmlElement* element)
{
    string w = element->Attribute("value");
    double x1 = atoi(element->Attribute("left"));
    double y1 = atoi(element->Attribute("top"));
    double x2 = atoi(element->Attribute("right"));
    double y2 = atoi(element->Attribute("bottom"));
    int bid = atoi(element->Attribute("id"));

    vector<Letter> chars;

    for (TiXmlElement* sub = element->FirstChildElement("char"); sub; sub = sub->NextSiblingElement("char"))
        chars.push_back(parseChar(sub));

    return Element(w, y1, x1, y2, x2, -1, bid, chars);
}

Letter Keywords::parseChar(TiXmlElement* element)
{
    string w = element->Attribute("value");
    double x1 = atoi(element->Attribute("left"));
    double y1 = atoi(element->Attribute("top"));
    double x2 = atoi(element->Attribute("right"));
    double y2 = atoi(element->Attribute("bottom"));
    int bid = atoi(element->Attribute("id"));
    return Letter(w, y1, x1, y2, x2, bid);
}

我将参数作为指针留下的唯一原因是TiXmlElement的{{1}}和FirstChildElement()函数返回的原因。通常情况下，我会将它们作为引用（NextSiblingElement()），这样更安全，因为您无法通过TiXmlElement &element。

如果由于性能原因确实需要避免复制，并且编译器不够智能自动执行此操作，则可以使用smart pointers，这是引用计数，因此您无需担心NULL他们。

delete

Answer 2

您通常不会“返回”指针。您可以将指针作为参数传递给函数，并在函数中为其指定值。由于指针是内存位置，因此当函数返回时，该值将保留在指针中。然后，您可以在将指针用于所需内容后进行任何内存管理。

返回值后删除指针

2 个答案: