Question

我正在使用JAXB和JSON实现jqGrid消费的通用java POJO包装器。这是一个CXF服务，所以我选择的marshaller库是Jettison或Jackson：

@XmlRootElement(name = "response")
public class JQGridResponseWrapper<T> {

private PaginatedResults<T> results;

public JQGridResponseWrapper() {
}

public JQGridResponseWrapper(PaginatedResults<T> results) {
    this.results = results;
}

@XmlElementWrapper(name = "records")
@XmlElement(name = "record")
public List<T> getRecords() {
    return results.getRecords();
}

@XmlElement(name = "pager")
public Pager getPager() {
    return results.getPager();
}
}

这是一个由通用包装器包装的示例POJO：

@XmlRootElement
public class Note {

private Long id;
private String subject;
private String description;

private Project project;

public Note() {}

public Note(Long id, String subject, String description, Project project) {

    this.id = id;
    this.subject = subject;
    this.description = description;
    this.project = project;
}

@XmlElement(name="noteId")
public Long getId() {
    return id;
}

public void setId(Long id) {
    this.id = id;
}

public String getSubject() {
    return subject;
}

public void setSubject(String subject) {
    this.subject = subject;
}

public String getDescription() {
    return description;
}

public void setDescription(String description) {
    this.description = description;
}

public Project getProject() {
    return project;
}

public void setProject(Project project) {
    this.project = project;
}

}

当编组到XML时，一切正常，所有类型都被正确映射，并且我得到一个包含<records>元素数组的父<record>元素。但是当编组到JSON（项目要求）时，'record'元素是未命名的，这使得jqGrid阻塞：

{"records":[
{"subject":"subject aaa",
 "description":"Description dsifj ofdisjo",
 "project":{
    "projectCode":"HWIIA",
    "description":"project description",
    "brand":null,
    "projectId":101
    },
 "noteId":201
},
{"subject":"subject bbb",
 "description":"Description odisfj doisjf odsijf",
 "project":{
    "projectCode":"HWIIA",
    "description":"project description",
    "brand":null,
    "projectId":101
    },
 "noteId":202
},
{"subject":"subject ccc",
"description":"Description oijgf gfoij jgifif",
"project":{
    "projectCode":"HWIIA",
    "description":"project description",
    "brand":null,
    "projectId":101
    },
"noteId":203
}
],
"pager"{
"recordsPerPage":10,
"currentPage":1,
"fromRecord":1,
"toRecord":3,
"totalRecords":3,
"totalPages":1}}

我需要为记录数组中的每条记录命名。是否有一种简单的方法可以使用Jettion或Jackson来完成这项工作？我搜索并搜索了网络，但找不到我目标编组库的直接解决方案。我确实看到了MOXY的一些答案，但是在这一点上我改变库是有问题的。非常感谢任何帮助。

使用Jettison或Jackson为jqGrid使用JAXB / JSON编组java列表

0 个答案: