Question

需要从数组中获取重复值，并获取下面的代码，但在AS3中运行良好

请有人将此AS3代码转换为AS2吗？

var array:Array = [1,2,3,4,3];

// create a dictionary and go through our array, pulling out the values
var dict:Dictionary = new Dictionary();
var len:int         = array.length;
for( var i:int = 0; i < len; i++ )
{
    var val:int = array[i]; // get the value from the array
    if( !( val in dict ) )  // if it's not in our dictionary, create a new array
        dict[val] = [];
    dict[val].push( i );    // add the index of the value to the array
}

// now go through our dictionary, finding the duplications
for( var key:* in dict )
{
    var indicies:Array = dict[key];
    if( indicies.length <= 1 )
        continue; // single value - ignore
    trace( "The value " + key + " is repeated " + indicies.length + " times. Indicies: " + indicies );
}

错误代码：
Séquence=Séquence1，layer = Calque 1，frame = 1，ligne 2 Impossible de charger la classe ou l'interface'Fictionary'。
Séquence=Séquence1，layer = Calque 1，frame = 1，ligne 3 Impossible de charger la classe ou l'interface'int'。
Séquence=Séquence1，layer = Calque 1，frame = 1，ligne 4 Impossible de charger la classe ou l'interface'int'。
Séquence=Séquence1，layer = Calque 1，frame = 1，ligne 6 Impossible de charger la classe ou l'interface'int'。
Séquence=Séquence1，layer = Calque 1，frame = 1，ligne 7'）'attendu
Séquence=Séquence1，layer = Calque 1，frame = 1，ligne 10'}'inattendu

Answer 1

怎么样：

var array:Array = [1,2,3,4,3];
var obj:Object = new Object();

for( var i:int = 0; i < array.length; i++ )
{
   if( obj[ array[i]] === undefined )
   {
        obj[ array[ i ]] = i;
   }
   else trace( "the value " + array[i] + " from location " + obj[ array[ i ]] + " is repeated at location " + i );
}

（这只是p代码。我面前没有编译器。）

你想对结果做什么？

Actionscript：将函数从AS3转换为AS2

1 个答案: