您好我正在尝试加入2个DataTables,其中一个包含3个不同的列作为主键,而另一个列与外键相同,这里是左数据表图像:
和Right DataTable Imge就是这个:
这里是我试图使用的代码,但没有返回,它应该
var query5 =
from ChanToNGrsToNgrDAnWal in chanToNGrsToNgrDAnWal.AsEnumerable()
join Node in node.AsEnumerable()
on new {
A = ChanToNGrsToNgrDAnWal.Field<int?>("diffusers_Id"),
B = ChanToNGrsToNgrDAnWal.Field<int?>("analogs_Id"),
C = ChanToNGrsToNgrDAnWal.Field<int?>("wallstats_Id") }
equals new {
A = Node.Field<int?>("diffusers_Id"),
B = Node.Field<int?>("analogs_Id"),
C = Node.Field<int?>("wallstats_Id")
}
select new
{
channel_Id = ChanToNGrsToNgrDAnWal.Field<int?>("channel_Id"),
number = ChanToNGrsToNgrDAnWal.Field<string>("number"),
nodeGroups_Id = ChanToNGrsToNgrDAnWal.Field<int>("nodeGroups_Id"),
analogNodeSerial = ChanToNGrsToNgrDAnWal.Field<string>("analogNodeSerial"),
diffuserNodeSerial = ChanToNGrsToNgrDAnWal.Field<string>("diffuserNodeSerial"),
wallStatNodeSerial = ChanToNGrsToNgrDAnWal.Field<string>("wallStatNodeSerial"),
diffusers_Id = ChanToNGrsToNgrDAnWal.Field<int?>("diffusers_Id"),
analogs_Id = ChanToNGrsToNgrDAnWal.Field<int?>("analogs_Id"),
wallstats_Id = ChanToNGrsToNgrDAnWal.Field<int?>("wallstats_Id"),
typeCode = Node.Field<string>("typeCode"),
node_Id = Node.Field<int?>("node_Id")
};
任何人都可以告诉我为什么会这样,或者我写的查询是错误的,请你们帮助我。
答案 0 :(得分:0)
根据您的示例数据,此处没有任何匹配项(零与空值不匹配)。如果由于您的应用程序逻辑而定,那么您可以将字段的值转换为int
而不是Nullable<int>
。在这种情况下,将为DbNull
个单元格提供默认值(零):
on new {
A = ChanToNGrsToNgrDAnWal.Field<int>("diffusers_Id"),
B = ChanToNGrsToNgrDAnWal.Field<int>("analogs_Id"),
C = ChanToNGrsToNgrDAnWal.Field<int>("wallstats_Id")
}
equals new {
A = Node.Field<int>("diffusers_Id"),
B = Node.Field<int>("analogs_Id"),
C = Node.Field<int>("wallstats_Id")
}