Question

我有一些SQL想要与ZendFW一起使用，但我无法让它工作，这让我发疯。我通过此查询得到了正确的结果：

SELECT DISTINCT e.festival_id FROM entries AS e, mail_log as m 
WHERE e.status = 1 
AND e.festival_id 
NOT IN (SELECT m.entry_id FROM entries AS e, mail_log as m WHERE m.entry_id = e.festival_id)

帮助将不胜感激。干杯：）

Answer 1

Goran的回答是最好的答案。但是如果你想要一个zend_db_table样式的查询，这将是另一种选择：

$sql = $table->select()
          ->setIntegrityCheck(false)
          ->from('entries', new Zend_Db_Expr('DISTINCT festival'))
          ->where('status = ?', 1)
          ->where('festival_id NOT IN (?)',new Zend_Db_Expr("SELECT m.entry_id FROM entries AS e, mail_log as m WHERE m.entry_id = e.festival_id"));

Answer 2

我不确定Zend_Db_Table是否能够处理子查询。

为什么需要使用Zend_Db_Table？

您可以使用Zend_Db :: query（）直接执行查询。

$db = Zend_Db_Table::getDefaultAdapter();
$db->query("SELECT DISTINCT e.festival_id FROM entries AS e, mail_log as m 
    WHERE e.status = 1 
    AND e.festival_id 
    NOT IN (SELECT m.entry_id FROM entries AS e, mail_log as m WHERE m.entry_id = e.festival_id)
");

Answer 3

就我而言，这有效：

$subselect = $db->select()
  ->from(array('u1' => 'users'), 'departmentId')
  ->joinInner(array('d' => 'demand'), 'u1.userId = d.adminId', null)
  ->where('d.demandId = ?', $demand->getId());

$select2 = $db->select()
  ->from(array('u' => 'users'))
  ->where('u.departmentId = ?', $subselect);

结果如下：

SELECT `u`.* FROM `users` AS `u` WHERE u.departmentId = (SELECT `u1`.`departmentId` FROM `users` AS `u1` INNER JOIN `demand` AS `d` ON u1.userId = d.adminId WHERE d.demandId = '1')

Answer 4

我也试试你sql.This是我的代码。

$select = $db->select()
      ->from(array('e' => ' entries'), array('festival_id'))
      ->distinct(true)
      ->where('e.status =?', 1)
      ->where('e.festival_id NOT IN (SELECT m.entry_id FROM entries AS e, mail_log as m WHERE m.entry_id = e.festival_id)')
      ->setIntegrityCheck(false);

我认为这段代码比其他代码更具可读性和简单性。

Zend_Db_Table子查询

4 个答案: