Question

我有一个问题从mysql转换为mysqli，我已经尝试了php文档说但我仍然无法得到它。任何帮助将不胜感激。

return (mysql_result(mysql_query("SELECT COUNT(id) FROM users WHERE (username = '$username' OR email = '$username') AND password = '$password'"), 0) == 1) ? $user_id : false;

我试过了：

return (mysqli_data_seek(mysqli_query($con,"SELECT COUNT(id) FROM users WHERE (username = '$username' OR email = '$username') AND password = '$password'"), 0) == 1) ? $user_id : false;

整个功能：

function login($username, $password){
$con=mysqli_connect("127.0.0.1","root","","frostbase");
    $user_id = user_id_from_username($username);


    $username = sanitize($username);
    $password = md5($password);

    return (mysqli_data_seek(mysqli_query($con,"SELECT COUNT(id) FROM users WHERE (username = '$username' OR email = '$username') AND password = '$password'"), 0) == 1) ? $user_id : false;
    mysqli_close($con);
}

Answer 1

你可以做得更好。

safeMysql是一个工具，可以帮助您将丑陋的旧的基于mysql API的代码转换为新的丑陋的mysqli基于API的代码，但使用更好的方法。

关键是您不得在应用程序代码中使用原始API调用，无论是mysql，mysqli还是PDO。但将它们包装在一个库中，该库将执行所有必需的操作，如数据绑定，提取，错误处理，分析等等。

坦率地说，你只需编写查询 - 其余的由lib完成：

$sql = "SELECT 1 FROM users WHERE (username = ?s OR email = ?s) AND password = ?s"; 
return (bool)$db->getOne($sql, $username, $username, $password);

或以函数的形式

function login($username, $password){
    global $con; // you have to connect ONCE per application
    $sql = "SELECT 1 FROM users WHERE (username = ?s OR email = ?s) AND password = ?s"; 
    return (bool)$con->getOne($sql, $username, $username, $password); 
}

我如何将其转换为mysqli

1 个答案: