模式和替换有问题。如何使替换回声成为最终产品,例如
INSERT INTO `table` (`person`, `file`) VALUES
('test','test'),
('test2','test2'),
('test3','test3');
我正在尝试将字符串插入SQL中,但我需要格式化下面的当前字符串才能这样做,我需要将字符串的最后一部分 test3:test3 或其他任何文本可能是关闭SQL模式('test3','test3');
<?php
$string = 'test:test test2:test2 test3:test3';
$pattern = '';
$replacement = '';
echo preg_replace($pattern, $replacement, $string);
?>
另外,它还可以有这样的字符串吗? 'test@test.com:test test2:test2'
,而电子邮件将始终在冒号之前。
答案 0 :(得分:1)
尝试这样的事情:
$string = 'test:test test2:test2 test3:test3';
$patterns = array("/([^\s:]+):([^\s:]+)/", "/\s++\(/");
$replacements = array("('$1', '$2')", ", (");
$sql = 'INSERT INTO `table` (`person`, `file`) VALUES ' . preg_replace($patterns, $replacements, $string) . ';';
echo $sql . "\n";
解释:
Regex 1
([^\s:]+) # match one or more chars other than white space chars and colons and store it in group 1
: # match a colon
([^\s:]+) # match one or more chars other than white space chars and colons and store it in group 2
Replacement 1
( # insert a '('
'$1' # insert what is matched in group 1 and surround it with single quotes
, # insert ', '
'$2' # insert what is matched in group 2 and surround it with single quotes
) # insert a ')'
Regex 2
\s++ # match one or more white space chars
\( # match a '('
Replacement 2
, ( # insert ', ('