所以我尝试制作一个乘法游戏。所以它有点有用,但是当我输入正确的答案时,它会输入两次“错误”......以及如果我输错了答案。
import sys #imports sys
random1=['1','2','3','4','5','6','7','8','9','10','11','12'] #makes a list with numbers 1-12
random2=['1','2','3','4','5','6','7','8','9','10','11','12'] #makes another list with numbers 1-12
from random import choice #gets a random number
while True: #makes the following code run in a loop
print "To exit this game type 'exit'" #prints stuff
theyputinstuffhere = raw_input("What is " + choice(random2) + " times " + choice(random1) + "? ") #asks the user things like 1*5 or some other random stuff.
if theyputinstuffhere == "exit": #if the user typed in 'exit' then exit the game
print "Now exiting game!" #prints stuff
sys.exit() #exits
elif theyputinstuffhere == int(choice(random2))*int(choice(random1)): #if what i typed is right, print stuff (I think i messed up here!)
print "Correct!" #print stuff
else:
print "Wrong!" #otherwise print stuff
我不知道我做错了什么帮助!!!!!!!!!!!!! QUICK !!!!!!!!!!!!!!!!!
答案 0 :(得分:1)
你正在使用选择两次,所以你问的问题可能是这样的:5 * 6
您的if语句可以检查类似的内容:11 * 4
您还将int与string进行比较,因此也将条件转换为带有条件的int。
另外,如果你使用了randrange()而没有创建一个列表,那么choice()对此来说是一个不好的函数。尝试将两个初始choice()返回值分配给变量,并在稍后的提示和条件中使用它们。
答案 1 :(得分:1)
这应该可以完美地运作
import sys
import random
while True:
num1 = random.randint(0,12)
num2 = random.randint(0,12)
print "To exit this game type 'exit'"
theyputinstuffhere = raw_input("What is " + str(num2) + " times " + str(num1) + "? ")
if theyputinstuffhere == "exit": #if the user typed in 'exit' then exit the game
print "Now exiting game!" #prints stuff
sys.exit() #exits
elif int(theyputinstuffhere) == num1*num2:
print "Correct!" #print stuff
else:
print "Wrong!"
使用random.randint
代替选择原因然后你不需要你关闭的列表!
当你使用ifre if语句时,你正在重置num1
和num2
现在它会重置每个循环
答案 2 :(得分:0)
而不是
theyputinstuffhere = raw_input("What is " + choice(random2) + " times " + choice(random1) + "? ") #asks the user things like 1*5 or some other random stuff.
if theyputinstuffhere == "exit": #if the user typed in 'exit' then exit the game
print "Now exiting game!" #prints stuff
sys.exit() #exits
elif int(theyputinstuffhere) == int(choice(random2))*int(choice(random1)): #if what i typed is right, print stuff (I think i messed up here!)
print "Correct!" #print stuff
else:
print "Wrong!" #otherwise print stuff
这样做:
num1 = choice(random1)
num2 = choice(random2)
theyputinstuffhere = raw_input("What is " + num1 + " times " + num2 + "? ") #asks the user things like 1*5 or some other random stuff.
if theyputinstuffhere == "exit": #if the user typed in 'exit' then exit the game
print "Now exiting game!" #prints stuff
sys.exit() #exits
elif theyputinstuffhere == int(num1)*int(num2): #if what i typed is right, print stuff (I think i messed up here!)
print "Correct!" #print stuff
else:
print "Wrong!" #otherwise print stuff
答案 3 :(得分:0)
对此问题的回答是>>>>>>回答CHRISTIAN CAREAGA !!!!!
import sys
import random
while True:
num1 = random.randint(0,12)
num2 = random.randint(0,12)
print "To exit this game type 'exit'"
theyputinstuffhere = raw_input("What is " + str(num2) + " times " + str(num1) + "? ")
if theyputinstuffhere == "exit": #if the user typed in 'exit' then exit the game
print "Now exiting game!" #prints stuff
sys.exit() #exits
elif int(theyputinstuffhere) == num1*num2:
print "Correct!" #print stuff
else:
print "Wrong!"
谢谢大家!!!!你们全都帮了!!! (对不起克里斯蒂安,我刚刚复制错了......)