Question

我正在使用xmlelement在oracle中编写一段html代码。

我当前的数据库存储这些数据

+---------+----------------+-----------------------+-----------+
| menu_id | title          | url                   | upper_lvl |
+---------+----------------+-----------------------+-----------+
|       1 | Forms          | null                  |         0 |
|       2 | Basic forms    | forms-basic.html      |         1 |
|       3 | Extended forms | forms-extended.html   |         1 |
|       4 | Validation     | forms-validation.html |         1 |
|       5 | Wizard321      | forms-wizard.html     |         1 |
+---------+----------------+-----------------------+-----------+

这是我想要的格式：

<ul class="dropdown-menu">
  <li>
      <a href="forms-basic.html">Basic forms</a>
  </li>
  <li>
      <a href="forms-extended.html">Extended forms</a>
  </li>
  <li>
      <a href="forms-validation.html">Validation</a>
  </li>
  <li>
      <a href="forms-wizard.html">Wizard</a>
  </li>
</ul>

我试图使用下面的代码来获取结果，但我知道它不起作用，因为内部查询返回多行。如果有人可以修改或其他解决方案，欢迎来到这里。

select 
  xmlelement("ul",
    xmlattributes('dropdown-menu' as "class"),
    xmlelement("li",
      xmlelement("a",
        xmlattributes(url as "href"),
        (select title from att1 where upper_lvl = 1)
      )
    )
  )

from att1
where menu_id = 1;

Answer 1

您需要使用XMLAgg（XML聚合函数）来实现此目的

select 
  xmlelement("ul", xmlattributes('dropdown-menu' as "class"),
      XMLAgg(xmlelement("li",
                        xmlelement("a",
                        xmlattributes(url as "href"),title) as "Menu Element"
                        ) 
            )
          ) as Menu
    from att1 where upper_lvl = 1

如果这不适合你，请告诉我

如何在xmlattributes中将多行放入一个单元格中

1 个答案: