我正在尝试编写一个通用方法来比较两个对象(我故意有两种不同的类型进入。第二种具有与第一种相同的属性。第一种只有更多。)。
我想确保属性具有相同的值。以下代码适用于我在对象中的大多数属性,但偶尔会抛出:
“对象与目标类型不匹配”
...错误
var valFirst = prop.GetValue(manuallyCreated, null) as IComparable;
public static bool SameCompare<T, T2>(T manuallyCreated, T2 generated){
var propertiesForGenerated = generated.GetType().GetProperties();
int compareValue = 0;
foreach (var prop in propertiesForGenerated) {
var valFirst = prop.GetValue(manuallyCreated, null) as IComparable;
var valSecond = prop.GetValue(generated, null) as IComparable;
if (valFirst == null && valSecond == null)
continue;
else if (valFirst == null) {
System.Diagnostics.Debug.WriteLine(prop + "s are not equal");
return false;
}
else if (valSecond == null) {
System.Diagnostics.Debug.WriteLine(prop + "s are not equal");
return false;
}
else if (prop.PropertyType == typeof(System.DateTime)) {
TimeSpan timeDiff = (DateTime)valFirst - (DateTime)valSecond;
if (timeDiff.Seconds != 0) {
System.Diagnostics.Debug.WriteLine(prop + "s are not equal");
return false;
}
}
else
compareValue = valFirst.CompareTo(valSecond);
if (compareValue != 0) {
System.Diagnostics.Debug.WriteLine(prop + "s are not equal");
return false;
}
}
System.Diagnostics.Debug.WriteLine("All values are equal");
return true;
}
答案 0 :(得分:3)
在.NET中的类型上定义的每个属性都是不同的,即使它们具有相同的名称。你必须这样做:
foreach (var prop in propertiesForGenerated)
{
var otherProp = typeof(T).GetProperty(prop.Name);
var valFirst = otherProp.GetValue(manuallyCreated, null) as IComparable;
var valSecond = prop.GetValue(generated, null) as IComparable;
...
当然,这并未考虑T
上定义的某些属性在T2
上可能不存在,反之亦然。
答案 1 :(得分:0)
因为manuallyCreated
不属于T2
类型。尝试在该类型上获取具有相同名称的属性对象,它应该可以工作(或者如果您假设T2中的所有属性也在T1中,您将获得更好的错误):
public static bool SameCompare<T, T2>(T manuallyCreated, T2 generated){
var propertiesForGenerated = typeof(T2).GetProperties();
int compareValue = 0;
foreach (var prop in propertiesForGenerated) {
var firstProperty = typeof(T).GetProperty(prop.Name);
var valFirst = firstProperty.GetValue(manuallyCreated, null) as IComparable;
var valSecond = prop.GetValue(generated, null) as IComparable;
...
}
}
答案 2 :(得分:0)
我相信最好让您需要比较的属性的接口,
然后我会继承IEqualityComparer<YourInterface>
以及Equals和GetHashCode
public bool Equals(YourInterface one, YourInterface two)
{
return this.GetHashCode(one) == this.GetHashCode(two);
}
public int GetHashCode(YourInterface test)
{
if(test == null)
{
return 0;
}
int hash = 0;
//// get hash or set int on each property.
return hash;
}