Question

有谁知道如何让以下代码工作？

def mixin(TargetClass, *args, **kwargs):
    """*args is a bunch of classes to mixin to the TargetClass"""
    if kwargs.get('name') is None:
        kwargs['name'] = '%s_mixed_with_%s' % (TargetClass.__name__, "".join(map(str, args)))

    class MixedClass(TargetClass, *args):
        pass

    MixedClass.__name__ = kwargs.get('name')
    return MixedClass

# assume for all intents and purposes that Foo, Bar, Baz, Bot, Quux, and Muck are Classes
# Foo should inherit from all of Bar, Baz, Bot, Quux, and Muck
def uber_foo = mixin(Foo, Bar, Baz, Bot, Quux, Muck, name="UberFoo")`

现在Python解释器（2.7.5）引发了以下错误：

TypeError：调用元类库时出错元类冲突：派生类的元类必须是其所有基类的元类的（非严格）子类

Answer 1

怎么样：

return type(kwargs.get('name'),(TargetClass,)+args,{})

而不是：

class MixedClass(TargetClass, *args):
    pass

MixedClass.__name__ = kwargs.get('name')
return MixedClass

当然，由于SyntaxError无效，您脚本的最后一行可能会引发def whatever = something。那应该是：

UberFoo = mixin(Foo,Bar,Baz,Bot,Quux,Muck,name='UberFoo')

在Python中同时混合多个类？

1 个答案: