在jsf中获取ipv4而不是ipv6

Question

我想获取远程计算机中客户端的IP地址。我正在使用此代码：

public static String getClientIpAddr(HttpServletRequest request) {
    String ip = request.getHeader("X-Forwarded-For");
    if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
        ip = request.getHeader("Proxy-Client-IP");
    }
    if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
        ip = request.getHeader("WL-Proxy-Client-IP");
    }
    if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
        ip = request.getHeader("HTTP_CLIENT_IP");
    }
    if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
        ip = request.getHeader("HTTP_X_FORWARDED_FOR");
    }
    if (ip == null || ip.length() == 0 || "unknown".equalsIgnoreCase(ip)) {
        ip = request.getRemoteAddr();
    }
    return ip;
}

但它始终会返回IPv6，有没有办法获得IPv4？

Answer 1

如果您获得IPv6地址，则使用IPv6。 IPv4和IPv6是不同的协议，客户端选择在两者都可用时使用哪个协议。

如果您需要客户端的IPv4地址，则可以通过不在DNS中公布IPv6地址来强制它们使用它。随着IPv6的部署越来越多，这将是个坏主意。支持两者都很好，因此最好使用IPv6来处理客户端。