计算动态日期范围

Question

之前我已经询问过有关此查询的信息，但我现在提出的问题与之前的问题完全不同。如果需要，请参阅here以获取上一个问题。

下面的代码，应该为一个人计算一个数字，它应该使用以下信息：

获取一个逗留时长并给每个范围一个分数，＆lt; - 这个有效

Acuity得分，＆lt; - 这有效

共患分数，＆lt; - 这有效

ER访问分数。 ＆lt; - 这不起作用

我将以自己为例：

说我2013年6月18日来到急诊室并被送往医院。出院后，我将有一段逗留时间，根据@T1中的案例陈述进行评分，Acuity也在那里计算。

在第二个查询中，我应该根据2013年6月18日的日期 计算我在过去6个月内来到急诊室的次数 。这一点让我感到非常悲痛，也是我整个查询失败的重点。对我来说棘手的是，每次有人进来，他们都会得到一个访问ID，但这个人只有一个MRN作为他们的唯一标识符。因此，根据每次访问的出院日期，我必须在最近180天内计算出有多少次进来。例如：

6-18-2013 MCP来到急诊室并被录取

2013年6月20日MCP出院

逗留时间= 2

Acuity = 3

ER访问MCP 6-18-2013（不计算在内）6-01-2013（算上这个），5-15-2013（算上这个）2-19-2013（数这个）1-01-2013（不计算在内）ER访问= 3不是5

重要的是要注意，一个人的访问得分，而不是该人自己，这是由于ER访问的日期范围限制。所以我可以在6月18日的访问中获得一个分数，并在7月30日的访问中获得不同的分数。

到目前为止，我已完整地给出了查询，以便可以评估从头到尾的逻辑。我正在使用SQL Server 2008。

LOS和急性IP评分查询

-- VARIABLE DECLARATION AND INITIALIZATION
SET ANSI_NULLS OFF
GO

DECLARE @SD DATETIME
DECLARE @ED DATETIME


-- QUERY ONE THAT GETS THE SCORING FOR THE LOS AND ACUITY --########--]

-- THESE ARE PATIENT ADMIT DATES
SET @SD = '2013-01-01'
SET @ED = '2013-01-31'

-- @T1  --------------------------------------------------------------]
-- TABLE DECLARATION WHERE ALL RESULTS WILL GET DEPOSITED OF THE FIRST
-- QUERY WILL GET DEPOSITED. THIS TABLE WILL GET USED IN CONJUNCTION 
-- WITH TWO OTHER TABLES IN ORDER TO COMPUTE THE FINAL   
DECLARE @T1 TABLE (
ENCOUNTER_ID VARCHAR(200)
, MRN VARCHAR(200)
, [PT AGE] VARCHAR(200)
, [PT NAME] VARCHAR(500)
, [DAYS STAY] VARCHAR(200)
, [LACE DAYS SCORE] INT
, [ACUTE ADMIT SCORE] VARCHAR(100)
, ARRIVAL DATETIME
)
----------------------------------------------------------------------]

-- @T1 RECORD INSERTIONS #############################################]
INSERT INTO @T1
SELECT
A.PT_NO
, A.MED_REC_NO
, A.PT_AGE
, A.PT_NAME
, A.DAYS_STAY
, A.LACE_DAYS_SCORE
, A.ACUTE_ADMIT_LACE_SCORE
, A.ADM_DATE
--####################################################################]

-- DAYS STAY, ACUTE ADMIT AND RELATED SCORING -------------------------
FROM
    (SELECT PT_NO
    , Med_Rec_No
    , Pt_Age
    , Pt_Name
    , Days_Stay
    , CASE
        WHEN Days_Stay < 1 THEN 0
        WHEN Days_Stay = 1 THEN 1
        WHEN Days_Stay = 2 THEN 2
        WHEN Days_Stay = 3 THEN 3
        WHEN Days_Stay BETWEEN 4 AND 6 THEN 4
        WHEN Days_Stay BETWEEN 7 AND 13 THEN 5
        WHEN Days_Stay >= 14 THEN 6
      END AS LACE_DAYS_SCORE
    , CASE
        WHEN PLM_PT_ACCT_TYPE = 'I' THEN 3
        ELSE 0
      END AS ACUTE_ADMIT_LACE_SCORE
    , ADM_DATE

    FROM SMSDSS.BMH_PLM_PTACCT_V
    WHERE DSCH_DATE BETWEEN @SD AND @ED
    AND Plm_Pt_Acct_Type = 'I'
)A

--SELECT * FROM @T1

以上结果应如下所示：

ENCOUNTER_ID| MRN | AGE | PT NAME | DAYS STAY | LACE DAYS STAY |ACUTE SCR | ARRIVAL
123456789   | 123 | 65  | MCP     |   5       |      4         |    3     | 6/18/2013

ER计数查询由@JoaoLeal修复：

-- ER VISITS QUERY
DECLARE @CNT TABLE (
MRN VARCHAR(100)
, VISIT_ID VARCHAR(100)
, VISIT_DATE DATETIME
, VISIT_COUNT INT
)

INSERT INTO @CNT
SELECT
A.MRN
, A.VISIT_ID
, A.VISIT_DATE
, COUNT(B.VISIT_ID) AS VISIT_COUNT

FROM
(SELECT MED_REC_NO AS MRN, VST_START_DTIME AS VISIT_DATE, PT_NO AS VISIT_ID 
FROM smsdss.BMH_PLM_PtAcct_V
WHERE
((
    PLM_PT_ACCT_TYPE = 'I'
    AND ADM_SOURCE NOT IN
        ('RA',
        'RP'
        )
    )
OR PT_TYPE = 'E')
AND vst_start_dtime BETWEEN @SD AND @ED)A

LEFT JOIN
(SELECT MED_REC_NO AS MRN, VST_START_DTIME AS VISIT_DATE, PT_NO AS VISIT_ID 
FROM smsdss.BMH_PLM_PtAcct_V
WHERE
((
    PLM_PT_ACCT_TYPE = 'I'
    AND ADM_SOURCE NOT IN
        ('RA',
        'RP'
        )
    )
OR PT_TYPE = 'E')
AND vst_start_dtime BETWEEN @SD AND @ED)B
ON A.MRN = B.MRN
AND A.VISIT_DATE > B.VISIT_DATE AND A.VISIT_DATE-180 <B.VISIT_DATE

GROUP BY A.MRN, A.VISIT_ID, A.VISIT_DATE
ORDER BY A.MRN


--SELECT * FROM @CNT

所需的输出是这样的：

MRN  |  Visit_ID  |  Visit_Date  |  Visit_Count
123  |  12345678  |  6/18/2013   |       1

合并症查询

-- CO MORBIDITY QUERY

DECLARE @CM TABLE (
ENCOUNTER_ID VARCHAR(200)
, [MRN CM] VARCHAR(200)
, NAME VARCHAR(500)
, [CC GRP ONE SCORE] VARCHAR(20)
, [CC GRP TWO SCORE] VARCHAR(20)
, [CC GRP THREE SCORE] VARCHAR(20)
, [CC GRP FOUR SCORE] VARCHAR(20)
, [CC GRP FIVE SCORE] VARCHAR(20)
, [CC LACE SCORE] INT
)
--#####################################################################

INSERT INTO @CM
SELECT
C.PT_NO
, C.MED_REC_NO
, C.PT_NAME
, C.PRIN_DX_CD_1
, C.PRIN_DX_CD_2
, C.PRIN_DX_CD_3
, C.PRIN_DX_CD_4
, C.PRIN_DX_CD_5
, CASE
    WHEN (C.PRIN_DX_CD_1+C.PRIN_DX_CD_2+C.PRIN_DX_CD_3+C.PRIN_DX_CD_4+C.PRIN_DX_CD_5) = 0 THEN 0
    WHEN (C.PRIN_DX_CD_1+C.PRIN_DX_CD_2+C.PRIN_DX_CD_3+C.PRIN_DX_CD_4+C.PRIN_DX_CD_5) = 1 THEN 1
    WHEN (C.PRIN_DX_CD_1+C.PRIN_DX_CD_2+C.PRIN_DX_CD_3+C.PRIN_DX_CD_4+C.PRIN_DX_CD_5) = 2 THEN 2
    WHEN (C.PRIN_DX_CD_1+C.PRIN_DX_CD_2+C.PRIN_DX_CD_3+C.PRIN_DX_CD_4+C.PRIN_DX_CD_5) = 3 THEN 3
    WHEN (C.PRIN_DX_CD_1+C.PRIN_DX_CD_2+C.PRIN_DX_CD_3+C.PRIN_DX_CD_4+C.PRIN_DX_CD_5) = 4 THEN 4
    WHEN (C.PRIN_DX_CD_1+C.PRIN_DX_CD_2+C.PRIN_DX_CD_3+C.PRIN_DX_CD_4+C.PRIN_DX_CD_5) = 5 THEN 5
    WHEN (C.PRIN_DX_CD_1+C.PRIN_DX_CD_2+C.PRIN_DX_CD_3+C.PRIN_DX_CD_4+C.PRIN_DX_CD_5) >= 6 THEN 6
  END AS CC_LACE_SCORE

FROM (
    SELECT distinct PT_NO
    , MED_REC_NO
    , PT_NAME
    , CASE
        WHEN PRIN_DX_CD IN (
        List of Codes
        )
        THEN 1
        ELSE 0
      END AS PRIN_DX_CD_1
    , CASE
        WHEN PRIN_DX_CD IN (
        List of Codes
        )
        THEN 2
        ELSE 0
    END AS PRIN_DX_CD_2
    , CASE
        WHEN PRIN_DX_CD IN (
        List of Codes
        )
        THEN 3
        ELSE 0
      END AS PRIN_DX_CD_3
    , CASE
        WHEN PRIN_DX_CD IN (
        List of Codes
        )
        THEN 4
        ELSE 0
      END AS PRIN_DX_CD_4
    , CASE
        WHEN PRIN_DX_CD IN (
        List of Codes
        )
        THEN 6
        ELSE 0
      END AS PRIN_DX_CD_5

      FROM smsdss.BMH_PLM_PtAcct_V

      WHERE dsch_Date BETWEEN @SD AND @ED


)C
GROUP BY C.PT_NO
, C.MED_REC_NO
, C.PT_NAME
, C.PRIN_DX_CD_1
, C.PRIN_DX_CD_2
, C.PRIN_DX_CD_3
, C.PRIN_DX_CD_4
, C.PRIN_DX_CD_5
ORDER BY (C.PRIN_DX_CD_1+C.PRIN_DX_CD_2+C.PRIN_DX_CD_3+C.PRIN_DX_CD_4+C.PRIN_DX_CD_5)
--SELECT * FROM @CM

所需的输出如下：

Visit_ID  |  MRN  |  Name  |  Grp 1  |  Grp 2  |  Grp 3  |  Grp 4  |  Grp 5  | Total
1234567   |  123  |  MCP   |    0    |    2    |   3     |    4    |    0    |   6 

完全放弃：

DECLARE @LACE_MSTR TABLE (
MRN VARCHAR(200)
,ENCOUNTER VARCHAR(200)
, AGE VARCHAR(30)
, NAME VARCHAR (500)
, [LACE DAYS SCORE] INT
, [LACE ACUTE IP SCORE] INT
, [LACE ER SCORE] INT
, [LACE COMORBID SCORE] INT
)

INSERT INTO @LACE_MSTR
SELECT
Q1.MRN
, Q1.ENCOUNTER_ID
, Q1.[PT AGE]
, Q1.[PT NAME]
, Q1.[LACE DAYS SCORE]
, Q1.[ACUTE ADMIT SCORE]
, CASE
    WHEN Q1.[MRN COUNT] IS NULL THEN 0
    WHEN Q1.[MRN COUNT] = 1 THEN 1
    WHEN Q1.[MRN COUNT] = 2 THEN 2
    WHEN Q1.[MRN COUNT] = 3 THEN 3
    WHEN Q1.[MRN COUNT] >= 4 THEN 4
    ELSE 0
  END AS [LACE ER SCORE]
, Q1.[CC LACE SCORE]

FROM 
(
    SELECT 
    DISTINCT T1.ENCOUNTER_ID
    , T1.MRN
    , T1.[PT AGE]
    , T1.[PT NAME]
    , T1.[LACE DAYS SCORE]
    , T1.[ACUTE ADMIT SCORE]
    , CNT.[MRN COUNT]
    , CM.[CC LACE SCORE]

    FROM
    @T1 T1
    LEFT OUTER JOIN @CNT CNT
    ON T1.MRN = CNT.MRN
    JOIN @CM CM
    ON CM.ENCOUNTER_ID = T1.ENCOUNTER_ID
)Q1

SELECT DISTINCT ENCOUNTER
, MRN
, AGE
, NAME
, [LACE DAYS SCORE]
, [LACE ACUTE IP SCORE]
, [LACE ER SCORE]
, [LACE COMORBID SCORE]
, [LACE DAYS SCORE]+[LACE ACUTE IP SCORE]+[LACE ER SCORE]+[LACE COMORBID SCORE] AS [TOTAL LACE]

FROM @LACE_MSTR

GROUP BY ENCOUNTER
, MRN
, AGE
, NAME
, [LACE DAYS SCORE]
, [LACE ACUTE IP SCORE]
, [LACE ER SCORE]
, [LACE COMORBID SCORE]

此查询对@CM ON @T1表的遇到号以及MR对ER访问计数和T1表进行连接。出于一些非常奇怪的原因，当我通过MRN进行@CM on @T1的最终连接时，我将获得单个Encounter数的多个记录：

ENCOUNTER     |     MRN     |     CM SCORE
12345         |    99999    |        9
12345         |    99999    |       11

Answer 1

ER访问MRN

请允许我通过创建抽象来简化您的查询。基本上对于每个MRN，您将能够获得结果集：MRN，Visit_ID，Visit_Date（我在下面称之为<your sub query>）

使用该列表，您可以运行以下查询以获取访问次数：

SELECT 
    A.MRN, 
    A.VISIT_ID, 
    A.VISIT_DATE, 
    COUNT(B.VISIT_ID) AS VISIT_COUNT FROM (<your sub query>) A
LEFT JOIN (<your sub query>) B ON 
    A.MRN = B.MRN AND 
    A.VISIT_DATE > B.VISIT_DATE AND A.VISIT_DATE - 180 < B.VISIT_DATE
GROUP BY A.MRN, A.VISIT_ID, A.VISIT_DATE

希望这有帮助

编辑：<your sub query>应该是这样的：

SELECT MED_REC_NO AS MRN, VST_START_DTIME AS VISIT_DATE, PT_NO AS VISIT_ID 
FROM smsdss.BMH_PLM_PtAcct_V
WHERE
((
    PLM_PT_ACCT_TYPE = 'I'
    AND ADM_SOURCE NOT IN
        ('RA',
        'RP'
        )
    )
OR PT_TYPE = 'E')