考虑以下类和方法:a()调用b(),然后调用c()。
public class ReThrower {
public static void a(int a1){
try{
a1+=1;
b(a1);
}
catch(ArithmeticException e){
System.out.println("Exception caught at a");
throw e;
}
}
public static void b(int b1){
try{
b1+=1;
c(b1);
}
catch(ArithmeticException e){
System.out.println("Exception caught at b");
throw e;
}
}
public static void c(int c1){
int zero=0,result;
try{
result=c1/zero;
}
catch(ArithmeticException e){
System.out.println("Exception caught at c");
e.printStackTrace();
throw e;
}
}
public static void main(String[] args) {
a(5);
}
}
当我运行上面的代码时,收到的初始输出是:
Exception caught at c
java.lang.ArithmeticException: / by zero
Exception caught at b
Exception caught at a
at com.atul.security.ReThrower.c(ReThrower.java:31)
at com.atul.security.ReThrower.b(ReThrower.java:20)
at com.atul.security.ReThrower.a(ReThrower.java:10)
at com.atul.security.ReThrower.main(ReThrower.java:46)
Exception in thread "main" java.lang.ArithmeticException: / by zero
at com.atul.security.ReThrower.c(ReThrower.java:31)
at com.atul.security.ReThrower.b(ReThrower.java:20)
at com.atul.security.ReThrower.a(ReThrower.java:10)
at com.atul.security.ReThrower.main(ReThrower.java:46)
即使在c()打印完整的堆栈跟踪之前,b()和a()中包含的sysout也已经执行过了。 但是,当我再次运行它时,输出会发生变化:
Exception caught at c
Exception caught at b
Exception caught at a
java.lang.ArithmeticException: / by zero
at com.atul.security.ReThrower.c(ReThrower.java:31)
at com.atul.security.ReThrower.b(ReThrower.java:20)
at com.atul.security.ReThrower.a(ReThrower.java:10)
at com.atul.security.ReThrower.main(ReThrower.java:46)
Exception in thread "main" java.lang.ArithmeticException: / by zero
at com.atul.security.ReThrower.c(ReThrower.java:31)
at com.atul.security.ReThrower.b(ReThrower.java:20)
at com.atul.security.ReThrower.a(ReThrower.java:10)
at com.atul.security.ReThrower.main(ReThrower.java:46)
鉴于这是单线程,为什么多次运行中的行为会发生变化?
答案 0 :(得分:3)
e.printStacktrace
打印到System.err
,而您使用System.out
打印其余行。当你打印到两个流the result can look out of order时。