我在文件夹中有不同的HTML文件。如何重命名文件,使其名称为:
1.HTML
2.HTML
3.html
...
答案 0 :(得分:2)
这可以做到:
i=1
for file in /your/folder/*
do
mv $file ${i}.html
i=$((i+1)) #((i++)) was giving errors (see comments)
done
它遍历/your/folder
中的所有文件,并根据不断增加的数字$i
重命名。
答案 1 :(得分:1)
这是我的剧本
#!/bin/sh
#
# batchrename - renames files like 01.ext, 02.ext ...
#
# format : batchrename <list of files>
# or: -r <extension> <<list of files> or <dir>>
# -r - recoursively
counter=0
extrec=""
if [ "$#" -lt "1" ]; then
echo -e "\n\t\tUsage:\n\tbatchrename [opt]\nopt:"
echo -e "-r <ext> <folder> (or file list) -- renames recoursively ALL files"
echo -e "\tin folder <folder> (or by file list given) with extension .<ext>"
echo -e "<folder> -- renames ALL files in folder given"
echo -e "<file list> -- renames ALL files of given filelist.\n\n"
exit 0
fi
Name="$*"
if [ "$1" = "-r" ]; then
extrec="$2"
shift
shift
Name="$*"
[ "$Name" = "" ] && Name="./"
fi
echo -e "\n\t\t\tRENAMING"
for file in $Name
do
file=`echo "$file" | sed "s/<>/ /g"`
if [ -d "$file" ];then
echo -e "\nDiving into \033[38m $file \033[39m"
cd "$file"
if [ "$extrec" != "" ]; then
batchrename -r $extrec `ls -1 | sed "s/\ /<>/g"`
else
batchrename `ls -1 | sed "s/\ /<>/g"`
fi
cd ../
continue
fi
ext=`ext "$file"`
if [ "$ext" = "ion" ]; then
continue
fi
if [ "$extrec" = "" -o "$ext" = "$extrec" ];then
counter=`expr $counter + 1`
echo -e "Progress: $counter files\r\c"
mv "$file" "rnmd$counter.$ext"
fi
done
echo -e "\n\n\t\t\tENDING"
digits=`echo $counter|awk '{print length ($0)}'`
cnt=1
while [ $digits -gt $cnt ]
do
f=`ls -S -1|grep "rnmd[0-9]\{$cnt\}\."`
rename rnmd rnmd0 $f
cnt=`expr $cnt + 1`
done
if [ "$counter" -gt "0" ]; then
rename rnmd "" rnmd*
fi
echo -e "\n\t\t\tDone !!!\n"
重命名后,所有文件看起来都像001.file,002.file,...等等。前导零的数量取决于文件的数量。因此,重命名后ls
将显示正确的文件顺序!
它使用中间脚本ext
:
#!/bin/sh
#
# ext - returns file suffix (case-unsensitive)
#
File="$*"
if [ -d "$File" ]; then
echo ""
exit 0
fi
EXT=`echo $File|sed 's/.\{1,\}\.//g'`
if [ "$EXT" = "$File" ]; then
EXT=""
fi
echo $EXT| tr '[:upper:]' '[:lower:]'