Question

我想用函数名字符串获取函数例如

class test(object):
  def fetch_function():
    print "Function is call"

 #now i want to fetch function  using  string 
 "fetch_function()"

结果应该是：函数是调用

Answer 1

如果您离开() fetch_function()，我可以使用getattr，我觉得比eval更安全：

class Test(object):

    def fetch_function():
        print "Function is called"

test_instance = Test()
my_func = getattr(test_instance, 'fetch_function')

# now you can call my_func just like a regular function:
my_func()

Answer 2

使用eval()：

eval("fetch_function()")

Answer 3

如上所述eval不安全，可以使用dict将函数映射到字符串并调用它

class test(object):
  dict_map_func = {'fetch_f': fetch_function}
  def fetch_function():
     print "Function is call"


test.dict_map_func['fetch_f']()

如何使用字符串获取函数？

3 个答案: