Question

使用以下代码时出现以下错误

The method onKeyDown(int, KeyEvent) is undefined for the type SherlockFragment

 public boolean onKeyDown(int KeyCode, KeyEvent event) {
        if ((KeyCode == KeyEvent.KEYCODE_BACK) && web.canGoBack()) {
            web.goBack();
            return true;
        }
        return super.onKeyDown(KeyCode, event);
    }

Answer 1

活动应该管理后退按钮而不是片段。如果您希望片段管理onKeyDown，则可以在OnKeyListener

返回的视图上附加getView()

@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
        Bundle savedInstanceState) {

    View view =  inflater.inflate(R.layout.left, container, false);
    view.setOnKeyListener( new OnKeyListener() {
          @Override
          public boolean onKey( View v, int keyCode, KeyEvent event ) {
                // here your code
          } 
     });
    return view;
}

Answer 2

经过少量研究。我找到了这个！希望它的帮助。

root =(ViewGroup) inflater.inflate(R.layout.setting_f_other, container, false);

    root.setOnKeyListener( new OnKeyListener() {
                      @Override
                      public boolean onKey(View v, int keyCode, KeyEvent event ) {
                          if (keyCode == KeyEvent.KEYCODE_BACK){
                            //Do something
                          }
                        return false;

                      } 
                 });

Answer 3

我会将这种事情从你的片段中删除。以下代码在我的MainActivity中为我工作，有4个选项卡，每个选项卡都有自己的Web视图。

@Override
public void onBackPressed() {
    // TODO Auto-generated method stub
    int currPage = mPager.getCurrentItem();
    WebView wv = null;
    switch (currPage) {
    case 0:
        wv = (WebView) mPager.getChildAt(currPage).findViewById(R.id.webView1);
        break;
    case 1:
        wv = (WebView) mPager.getChildAt(currPage).findViewById(R.id.webView2);
        break;
    case 2:
        wv = (WebView) mPager.getChildAt(currPage).findViewById(R.id.webView3);
        break;
    case 3:
        wv = (WebView) mPager.getChildAt(currPage).findViewById(R.id.webView4);
        break;
    }

    if (wv != null) {
        if (wv.canGoBack()) {
            wv.goBack();
        } else {
            super.onBackPressed();
        }
    } else {
        super.onBackPressed();
    }
}

编辑：我在第四个选项卡上遇到了麻烦，我的解决方案是在我的片段（Tab0.java）中设置webView静态。然后直接在我的主要活动中引用它。

switch (currPage) {
    case 0:
        wv = Tab0.webView;
        break;
    case 1:
        wv = Tab1.webView;
        break;
    case 2:
        wv = Tab2.webView;
        break;
    case 3:
        wv = Tab3.webView;
        break;
    }

SherlockFragment中未定义的onKeyDown

3 个答案: