Question

#include <vector>
#include <iostream>
#include <algorithm>
#include <iterator>
using namespace std;

int main()
{
  int arrA[] = {1, 2, 3, 4, 5, 6, 7, 8, 9};
  vector<int> vecIntA(arrA, arrA+sizeof(arrA)/sizeof(arrA[0]));

  vector<int> vecIntB(vecIntA.size());

  //copy((vecIntA.rbegin()+3).base(), (vecIntA.rbegin()+1).base(),  vecIntB.begin()); // OK    

  vector<int>::iterator s = (vecIntA.rbegin()+3).base();
  vector<int>::iterator e = (vecIntA.rbegin()+1).base();
  cout << "s: " << *s << ", e: " << *e << endl;
  reverse_copy(s, e,  vecIntB.begin()); // error: function call has aggregate value

  //copy(vecIntB.begin(), vecIntB.end(), ostream_iterator<int>(cout, ","));
  cout << endl;
}

问题＆GT;如何解决“错误：函数调用有聚合值”的问题？

以上代码适用于VS2010，但不适用于ubuntu12.04 + clang ++ 3.2或g ++ 4.6.3

谢谢

//更新//

//参考：Flags to enable thorough and verbose g++ warnings

g++ $1.cpp -o $1 -g -O -Wall -Weffc++ -pedantic  \
-pedantic-errors -Wextra  -Wall -Waggregate-return -Wcast-align \
-Wcast-qual  -Wchar-subscripts  -Wcomment -Wconversion \
-Wdisabled-optimization \
-Werror -Wfloat-equal  -Wformat  -Wformat=2 \
-Wformat-nonliteral -Wformat-security  \
-Wformat-y2k \
-Wimport  -Winit-self  -Winline \
-Winvalid-pch   \
-Wunsafe-loop-optimizations  -Wlong-long -Wmissing-braces \
-Wmissing-field-initializers -Wmissing-format-attribute   \
-Wmissing-include-dirs -Wmissing-noreturn \
-Wpacked  -Wpadded -Wparentheses  -Wpointer-arith \
-Wredundant-decls -Wreturn-type \
-Wsequence-point  -Wshadow -Wsign-compare  -Wstack-protector \
-Wstrict-aliasing -Wstrict-aliasing=2 -Wswitch  -Wswitch-default \
-Wswitch-enum -Wtrigraphs  -Wuninitialized \
-Wunknown-pragmas  -Wunreachable-code -Wunused \
-Wunused-function  -Wunused-label  -Wunused-parameter \
-Wunused-value  -Wunused-variable  -Wvariadic-macros \
-Wvolatile-register-var  -Wwrite-strings \
-std=c++0x

Answer 1

-Waggregate-return -Werror

您指定返回的聚合值为错误。虽然理论上不是。

<强> -Waggregate回
如果定义或调用任何返回结构或联合的函数，则发出警告。（在您可以返回的语言中数组，这也会引发警告。）

您可能想要删除此标记

std :: reverse_copy“错误：函数调用具有聚合值”

1 个答案: