Question

我想将num1和num2转换为列表并打印出来，有关如何进行此操作的任何输入？

num1 = 12345
num2 = 34266 73628


print num1
print num2

EXPECTED OUTPUT:-

['12345']
['34266','73628']

Answer 1

我将假设num1和num2都是字符串（否则您会出现语法错误）。您可以使用str.split()：

>>> num1 = '12345'
>>> num2 = '34266 73628'
>>> num1.split()
['12345']
>>> num2.split()
['34266', '73628']

Answer 2

让它们成为字符串，这样你就可以使用split，然后将它们变成整数!!

num1 = '12345'
num2 = '34266 73628'
def func(number):
    num = number.split()
    return [int(i) for i in num]

>>> func(num1)
[12345]
>>> 
>>> func(num2)
[34266, 73628]

Answer 3

n1 = '1234 456' #note the single quotes
n2 = '567 879'

def foo(num):
  return num.split()

foo(n1)
foo(n2)

输出：

['1234', '456']
['567', '789']

Answer 4

num1 = '12345'
num2 = '12345 67890'
#Note: Both must be strings

#Option 1(Recommended)
print num1.split()
print num2.split()

#Option 2
import shlex
print shlex.split(num2)

#Option 3
import re
print re.split(' ', num2)

#If the array needs to be of ints:
result1 = [int(item) for item in num1.split()]
result2 = [int(item) for item in num2.split()]

Answer 5

num1 = [12345]
num2 = [34266, 73628]


print num1
print num2

打印列表作为输出

5 个答案: