Question

我有一个脚本需要用户在文本框中输入。用户点击进入或单击“确定”后，必须将文本框中的数据传输到命令。这是代码的文本框部分。我只是几个月的PS。随意批评：）

    [void] [System.Reflection.Assembly]::LoadWithPartialName("System.Drawing") 
    [void] [System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms")
    $objForm = New-Object System.Windows.Forms.Form;
    $objForm.Text = "Enter Patch Number";
    $objForm.Size = New-Object System.Drawing.Size(100,100); 
    $objForm.StartPosition = "CenterScreen";
    $InputBox = New-Object System.Windows.Forms.TextBox
    $InputBox.Location = New-Object System.Drawing.Size(20,50)  
    $InputBox.Size = New-Object System.Drawing.Size(150,20) 
    $Form.Controls.Add($InputBox) 
    $Button = New-Object System.Windows.Forms.Button 
    $Button.Location = New-Object System.Drawing.Size(400,30) 
    $Button.Size = New-Object System.Drawing.Size(110,80) 
    $Button.Text = "Send to Patch Command" 
    $Button.Add_Click({$version}) 
    $Form.Controls.Add($Button) 
    $wks=$InputBox.text
    .\anp deploypatch -patch=$version
    $Form.Add_Shown({$Form.Activate()})
    [void] $Form.ShowDialog()

这是必须将用户输入传送到最后的命令。正确执行此cmd的一个示例是...... 。\ anp deploypatch -patch = 437.1237

换句话说，用户在上面以粗体键入项目并点击输入，并根据用户输入的版本执行命令。我想要的主要是如何将用户输入到我想要的命令中。

Answer 1

您可以尝试以下代码。在原始代码中$form不存在，控件位置是随机的，并且回车键未链接到按钮。

[void] [System.Reflection.Assembly]::LoadWithPartialName("System.Drawing") 
[void] [System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms")
$objForm = New-Object System.Windows.Forms.Form;
$objForm.Text = "Enter Patch Number";
$objForm.Size = New-Object System.Drawing.Size(200,200); 
$objForm.StartPosition = "CenterScreen";
$InputBox = New-Object System.Windows.Forms.TextBox
$InputBox.Location = New-Object System.Drawing.Point(20,20)  
$InputBox.Size = New-Object System.Drawing.Size(150,20) 
$objForm.Controls.Add($InputBox) 
$Button = New-Object System.Windows.Forms.Button 
$Button.Location = New-Object System.Drawing.Point(50,50) 
$Button.Size = New-Object System.Drawing.Size(110,80) 
$Button.Text = "Send to Patch Command"
$Button.Add_Click({$objForm.Close()}) 
$objForm.AcceptButton = $Button # the button is linked to the enter key
$objForm.Controls.Add($Button) 
$wks=$InputBox.text
$objForm.Add_Shown({$objForm.Activate()})
[void] $objForm.ShowDialog()
$version = $InputBox.Text
#$version
.\anp deploypatch -patch=$version

Answer 2

以下似乎可以解决这个问题让我知道你是怎么过的。

[void] [System.Reflection.Assembly]::LoadWithPartialName("System.Drawing") 
[void] [System.Reflection.Assembly]::LoadWithPartialName("System.Windows.Forms")
$Form = New-Object System.Windows.Forms.Form;
$Form.Text = "Enter Patch Number";
$Form.Size = New-Object System.Drawing.Size(500,200); 
$Form.StartPosition = "CenterScreen";

$InputBox = New-Object System.Windows.Forms.TextBox
$InputBox.Location = New-Object System.Drawing.Size(20,50)  
$InputBox.Size = New-Object System.Drawing.Size(150,20)
$InputBox.text = ""  
$Form.Controls.Add($InputBox) 



$Button = New-Object System.Windows.Forms.Button 
$Button.Location = New-Object System.Drawing.Size(400,30) 
$Button.Size = New-Object System.Drawing.Size(110,80) 
$Button.Text = "Send to Patch Command" 
$Button.Add_Click({patch}) 
$Form.Controls.Add($Button) 

Function patch {
$wks=$InputBox.text
Invoke-Expression "\anp deploypatch -patch='$wks'"
}

$Form.Add_Shown({$Form.Activate()})
[void] $Form.ShowDialog()

从文本框中管道信息

2 个答案: