Question

我在具有现有属性的现有模型上使用scaffold_controller生成器，但是生成的视图表单没有相应模型属性的任何输入控件 - 它们只是空表单。这是为什么？

例如：

rails generate scaffold_controller User --skip --no-test-framework

用户已有name和email属性的位置应生成包含姓名和电子邮件字段的表单...

Answer 1

这是应该做的。在调用scaffold_controller时，您告诉生成器不使用模型。如果你想在视图中有表单属性，你需要像普通的脚手架一样将它们传递给生成器。

rails g scaffold_controller User name email

Answer 2

我同意，当信息只是坐在模型中时，必须自己键入所有属性，存在拼写错误的名称或类型的危险。这是我编写的用于插入列名称和类型的猴子补丁（至少在Rails 4中）。将此代码放在＃{Rails.root} / config / initializers目录中的.rb文件中：

# patch to scaffold_controller to read model attributes
# if none specified on command line (and model exists)
# usage: rails g scaffold_controller <MODEL>

if ARGV.size > 0 and ARGV[0] == "scaffold_controller"
    puts "\n\n\n\n"
    puts "monkey patch attributes at #{Time.now}"

    Rails::Generators::NamedBase.class_eval do

        # parse_attributes! converts name:type list into GeneratedAttribute array
        # must be protected; thor enumerates all public methods as commands
        # and as I found out will call this and crash otherwise
        protected
        def parse_attributes! #:nodoc:
          # get model columns into col:type format
          self.attributes = get_model_attributes if not self.attributes or self.attributes.empty?
          # copied from default in named_base.rb
          self.attributes = (self.attributes || []).map do |attr|
            Rails::Generators::GeneratedAttribute.parse(attr)
          end
        end

        # get model columns if no attributes specified on command line
        # fake it by creating name:type args
        private
        def get_model_attributes
            # fill from model
            begin
                mdl = class_name.to_s.constantize
                # don't edit id, foreign keys (*_id), timestamps (*_at)
                attrs = mdl.columns.reject do |a|
                    n = a.name
                    n == "id" or n.end_with? "_id" or n.end_with? "_at"
                end .map do |a|
                    # name:type just like command line
                    a.name+":"+a.cast_type.type.to_s
                end
                puts "model_attributes(#{class_name})=#{attrs}"
                return attrs
            rescue => ex
                puts ex
                puts "problem with model #{class_name}"
                return nil
            end
        end

    end

end

Answer 3

在rails 5中，您可以使用以下代码获取类型列的列表。

Model.columns.reject{|n| n.name == "id" or n.name == "created_at" or n.name == "updated_at" }.map{|i| "#{i.name}:#{i.type}"}.join(" ")

稍后，您可以粘贴输出接线柱g scaffold_controller模型

Rails scaffold_controller生成器不会将模型属性应用于视图

3 个答案: