我有一个我用3 -4部分构建的查询。一旦我使用join添加union join，这将需要超过140secs才能运行。如何更改联合联接以更快地执行它。
SELECT
testing.CLIENTID,
testing.COMPANY,
testing.CONTACT,
testing.CONTACTID,
`orders`.`ORDERNO` AS `ORDERNO`,
`orders`.`BIDNO` AS `BIDNO`,
`projects`.`PROJID` AS `PROJID`,
`projects`.`PROJCODE` AS `PROJCODE`,
`projects`.`StartDate` AS `StartDate`,
`category`.`type` AS `CATEGORY`,
`projects`.`country` AS `COUNTRY`,
`projects`.`VALUE` AS `VALUE`,
`projects`.`PROCESSOR` AS `PROCESSOR`,
`projects`.`NES` AS `NES`,
`projects`.`SPECSALE` AS `SPECSALE`,
`projects`.`OFFICE` AS `OFFICE`,
`projects`.`LORM` AS `LORM`,
`lookupcountry`.`REGION` AS `REGION`
FROM
(
(
(
(
(
(
SELECT
contactmerge.CLIENTID,
contactmerge.CONTACT,
contactmerge.CONTACTID,
accountmerge.COMPANY
FROM
(
SELECT
`hdb`.`contacts`.`CONTACTID` AS `CONTACTID`,
`hdb`.`contacts`.`CLIENTID` AS `CLIENTID`,
concat(
`hdb`.`contacts`.`FIRSTNAME`,
" ",
`hdb`.`contacts`.`LASTNAME`
) AS CONTACT,
_utf8 'paradox' AS `SOURCEDATABASE`
FROM
`hdb`.`contacts`
UNION
SELECT
`sugarcrm`.`contacts`.`id` AS `CONTACTID`,
`sugarcrm`.`accounts_contacts`.`account_id` AS `CLIENTID`,
concat(
`sugarcrm`.`contacts`.`first_name`,
" ",
`sugarcrm`.`contacts`.`last_name`
) AS CONTACT,
_utf8 'sugar' AS `SOURCEDATABASE`
FROM
(
(
(
(
`sugarcrm`.`contacts`
LEFT JOIN `sugarcrm`.`email_addr_bean_rel` ON (
(
(
`sugarcrm`.`contacts`.`id` = `sugarcrm`.`email_addr_bean_rel`.`bean_id`
)
AND (
(
`sugarcrm`.`email_addr_bean_rel`.`primary_address` = 1
)
OR (
(
`sugarcrm`.`email_addr_bean_rel`.`primary_address` IS NOT NULL
)
AND (
`sugarcrm`.`email_addr_bean_rel`.`primary_address` <> 0
)
)
)
)
)
)
LEFT JOIN `sugarcrm`.`accounts_contacts` ON (
(
`sugarcrm`.`contacts`.`id` = `sugarcrm`.`accounts_contacts`.`contact_id`
)
)
)
JOIN `sugarcrm`.`email_addresses` ON (
(
`sugarcrm`.`email_addr_bean_rel`.`email_address_id` = `sugarcrm`.`email_addresses`.`id`
)
)
)
LEFT JOIN `sugarcrm`.`accounts` ON (
(
`sugarcrm`.`accounts`.`id` = `sugarcrm`.`accounts_contacts`.`account_id`
)
)
)
) AS contactmerge
LEFT JOIN (
SELECT
CLIENTID,
`hdb`.`clients`.`COMPANY` AS `COMPANY`
FROM
`hdb`.`clients`
UNION
SELECT
id AS CLIENTID,
`sugarcrm`.`accounts`.`name` AS `COMPANY`
FROM
`sugarcrm`.`accounts`
) AS accountmerge ON contactmerge.CLIENTID = accountmerge.CLIENTID
) AS testing
)
JOIN `orders` ON (
(
`testing`.`CONTACTID` = `orders`.`CONTACTID`
)
)
)
JOIN `projects` ON (
(
`orders`.`ORDERNO` = `projects`.`ORDERNO`
)
)
)
JOIN `category` ON (
(
`category`.`category_id` = `projects`.`category_id`
)
)
)
LEFT JOIN `lookupcountry` ON (
(
CONVERT (
`lookupcountry`.`COUNTRY` USING utf8
) = CONVERT (
`projects`.`country` USING utf8
)
)
)
)
ORDER BY
`testing`.`COMPANY`,
`projects`.`StartDate`
名为testing的表别名是执行时间很长的表。我需要将其转换为视图
原始查询，没有加入sugarcrm。
SELECT
`clients`.`CORPORATE` AS `CORPORATE`,
`clients`.`COMPANY` AS `COMPANY`,
`clients`.`CLIENTID` AS `CLIENTID`,
`contacts`.`CONTACTID` AS `CONTACTID`,
concat(
`contacts`.`LASTNAME`,
`contacts`.`FIRSTNAME`,
`contacts`.`INITIALS`
) AS `Contact`,
`orders`.`ORDERNO` AS `ORDERNO`,
`orders`.`BIDNO` AS `BIDNO`,
`projects`.`PROJID` AS `PROJID`,
`projects`.`PROJCODE` AS `PROJCODE`,
`projects`.`StartDate` AS `StartDate`,
`category`.`type` AS `CATEGORY`,
`projects`.`country` AS `COUNTRY`,
`projects`.`VALUE` AS `VALUE`,
`projects`.`PROCESSOR` AS `PROCESSOR`,
`projects`.`NES` AS `NES`,
`projects`.`SPECSALE` AS `SPECSALE`,
`projects`.`OFFICE` AS `OFFICE`,
`projects`.`LORM` AS `LORM`,
`lookupcountry`.`REGION` AS `REGION`
FROM
(
(
(
(
(
`clients`
JOIN `contacts` ON (
(
`clients`.`CLIENTID` = `contacts`.`CLIENTID`
)
)
)
JOIN `orders` ON (
(
`contacts`.`CONTACTID` = `orders`.`CONTACTID`
)
)
)
JOIN `projects` ON (
(
`orders`.`ORDERNO` = `projects`.`ORDERNO`
)
)
)
JOIN `category` ON (
(
`category`.`category_id` = `projects`.`category_id`
)
)
)
LEFT JOIN `lookupcountry` ON (
(
CONVERT (
`lookupcountry`.`COUNTRY` USING utf8
) = CONVERT (
`projects`.`country` USING utf8
)
)
)
)
ORDER BY
`clients`.`CORPORATE`,
`clients`.`COMPANY`,
`contacts`.`LASTNAME`,
`projects`.`StartDate`
答案 0 :(得分：2)
您从sugarcrm.contacts左下角加入Sugarcrm.email_addr_bean_rel 在id = bean_id上没问题，但是你对Primary_Address的测试= 1 OR（主地址IS NOT NULL和primary_address＆lt;＆gt; 0）是浪费。
非空意味着它有一个值。 1的第一个限定符是好的，但随后 你测试任何不等于0的地址（因此1是，但是2,3,400,1809或者是2） 任何其他数字。那么为什么不采取我如何简化它。
SELECT
O.ORDERNO,
O.BIDNO,
CASE when c.ContactID IS NULL
then sc.id
ELSE c.contactid END as ContactID,
CASE when c.ContactID IS NULL
then sac.account_id
ELSE c.clientid END as ClientID,
CASE when c.ContactID IS NULL
then concat( sc.first_name, " ", sc.last_name )
ELSE concat( c.FIRSTNAME, " ", c.LASTNAME ) END as Contact,
CASE when c.ContactID IS NULL
then sCli.`name`
ELSE cCli.Company END as Company,
CASE when c.ContactID IS NULL
then _utf8 'sugar'
ELSE _utf8 'paradox' END as SOURCEDATABASE,
P.PROJID,
P.PROJCODE,
P.StartDate,
Cat.`type` AS CATEGORY,
P.`country` AS COUNTRY,
P.`VALUE` AS `VALUE`,
P.PROCESSOR,
P.NES,
P.SPECSALE,
P.OFFICE,
P.LORM,
LC.REGION
FROM
orders O
JOIN projects P
ON O.ORDERNO = P.ORDERNO
JOIN category Cat
ON P.category_id = Cat.category_id
LEFT JOIN lookupcountry LC
ON CONVERT( P.`country` USING utf8 ) = CONVERT( LC.COUNTRY USING utf8 )
LEFT JOIN hdb.contacts c
ON O.ContactID = c.ClientID
LEFT JOIN hdb.clients cCli
ON c.ClientID = cCli.ClientID
LEFT JOIN sugarcrm.contacts sc
ON O.ContactID = sc.id
LEFT JOIN sugarcrm.accounts sCli
ON sc.id = sCli.id
LEFT JOIN sugarcrm.accounts_contacts sac
ON sc.id = sac.contact_id
LEFT JOIN sugarcrm.accounts Acc
ON sac.account_id = Acc.id
LEFT JOIN sugarcrm.email_addr_bean_rel EABR
ON sc.id = EABR.bean_id
AND EABR.primary_address IS NOT NULL
LEFT JOIN sugarcrm.email_addresses EA
ON EABR.email_address_id = EA.id
ORDER BY
CASE when c.ContactID IS NULL
then sCli.`name`
ELSE cCli.Company END,
P.StartDate
我不介意帮忙，但从现在开始，你应该看看我在做什么......建立关系......从你的数据（订单）的基础开始，看看一条路径关于如何连接到“联系人”表...写这些连接（作为左连接）。然后，写下您到SUGAR帐户联系人的路径并写下THOSE联接（也是左联接）。不要尝试预先查询所有可能的联系人，而是使用CASE / WHEN来确定基于空路由获得哪些联系，而不仅仅是我与联系人，客户，公司等的联系。您将从一条路径获取数据与其他人相比......只是保持一致。