Question

我有一个shell脚本来执行以下操作

sudo作为用户（johnsmith）并执行一些事情
退出该用户并检查网址状态
如果status不等于1，则ssh到另一台服务器并执行a 脚本。

但是当我运行它时，'ENDBASH'内的行根本没有被执行。

     #!/bin/ksh
     echo "Outside ENDBASH ${@##*/}"

    sudo -u johnssmith bash <<'ENDBASH'  

    echo "Inside ENDBASH ${@##*/}"

    #Obtaining the new version file
    for file in "${@##*/}"
     do
     if echo "$file" | grep -E "abc_cde_efg"; then
         echo "Version found: $file"
    else
           echo "Version not found"
    fi
    done        
    exit
ENDBASH

urlArray=('http://server:port/servicename1/services/servicename1?wsdl' 'http://server:port/servicename2/services/servicename2?wsdl')

status=0
    for url in "${urlArray[@]}"
     do
       result=`curl -s $url`

        if (echo $result | grep '<?xml' >/dev/null 2>&1); then
           service=$(echo $url | cut -d"/" -f4)
           echo "$service is Running"
      else
           service=$(echo $url | cut -d"/" -f4)
          echo "$service is not Running"
         status=1
        fi
     done    
if [ $status != 1 ] ; then
 ssh -t username@hostname /home/dev_was/test1.sh 
fi

Answer 1

您需要将脚本收到的参数显式传递给内部脚本：

sudo -u johnssmith bash -s "$@" <<'ENDBASH'

shell脚本无法正常工作

1 个答案: