我有一个表'order',其中列几乎看起来像这样:
| order_id | shop_id | order_total | currency | created_at |
现在我想进行查询,返回一个如下所示的表:
| interval | currency | sum |
其中interval是日期的间隔,currency是货币,sum是该区间中该货币的所有订单的总和。一个例子可能是:
| 2012-08-12-2012-09-12 | EUR | 540922 |
| 2012-08-12-2012-09-12 | DKK | 43215 |
| 2012-09-12-2012-10-12 | EUR | 123643 |
| 2012-09-12-2012-10-12 | DKK | 0 |
我已经有一个指示货币的查询,但我不知道如何让它考虑到货币..任何想法?
这是我现在使用的查询示例。真正的查询当然是由代码生成的,这只是一个例子。
SELECT CASE
WHEN created_at BETWEEN '2012-08-12' AND '2012-09-12' THEN '2012-08-12-2012-09-12'
WHEN created_at BETWEEN '2012-09-12' AND '2012-10-12' THEN '2012-09-12-2012-10-12'
WHEN created_at BETWEEN '2012-10-12' AND '2012-10-14' THEN '2012-10-12-2012-10-14'
end AS intrvl,
Sum(order_total)
FROM `order` o
WHERE shop_id = 4
AND created_at BETWEEN '2012-08-12' AND '2012-11-17'
GROUP BY CASE
WHEN created_at BETWEEN '2012-08-12' AND '2012-09-12' THEN '2012-08-12-2012-09-12'
WHEN created_at BETWEEN '2012-09-12' AND '2012-10-12' THEN '2012-09-12-2012-10-12'
WHEN created_at BETWEEN '2012-10-12' AND '2012-10-14' THEN '2012-10-12-2012-10-14'
end
/的Morten
答案 0 :(得分:11)
通过子句
将货币添加到您的选择和分组中SELECT CASE
WHEN created_at BETWEEN '2012-08-12' AND '2012-09-12' THEN '2012-08-12-2012-09-12'
WHEN created_at BETWEEN '2012-09-12' AND '2012-10-12' THEN '2012-09-12-2012-10-12'
WHEN created_at BETWEEN '2012-10-12' AND '2012-10-14' THEN '2012-10-12-2012-10-14'
end AS intrvl,
currency,
Sum(order_total)
FROM `order` o
WHERE shop_id = 4
AND created_at BETWEEN '2012-08-12' AND '2012-11-17'
GROUP BY CASE
WHEN created_at BETWEEN '2012-08-12' AND '2012-09-12' THEN '2012-08-12-2012-09-12'
WHEN created_at BETWEEN '2012-09-12' AND '2012-10-12' THEN '2012-09-12-2012-10-12'
WHEN created_at BETWEEN '2012-10-12' AND '2012-10-14' THEN '2012-10-12-2012-10-14'
end,
currency