Question

我想将json值传递给servlet来处理请求。

在客户端，我可以制作具有特殊字符的对象，例如“＆amp;” 。

我已将输入作为

"<h3>Welcome to ERP your name is #NAME#</h3>\n\n<h3>&nbsp;</h3>\n"

我使用

从json对象中检索值

request.getParameter("jsonVal")

通过这样调用，“＆amp; nbsp”之后的json值，不是由servlet采用的。输出是

"\"<h3>Welcome to ERP your name is #NAME#</h3>\\n\\n<h3>

并将错误显示为：

org.json.JSONException: Unterminated string at character 206
at org.json.JSONTokener.syntaxError(Unknown Source)
at org.json.JSONTokener.nextString(Unknown Source)
at org.json.JSONTokener.nextValue(Unknown Source)
at org.json.JSONObject.<init>(Unknown Source)
at org.json.JSONTokener.nextValue(Unknown Source)
at org.json.JSONArray.<init>(Unknown Source)
at org.json.JSONTokener.nextValue(Unknown Source)
at org.json.JSONObject.<init>(Unknown Source)
at org.json.JSONTokener.nextValue(Unknown Source)
at org.json.JSONObject.<init>(Unknown Source)
at org.json.JSONObject.<init>(Unknown Source)
at erp.controller.Controller.doPost(Controller.java:49)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:647)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:222)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:472)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:171)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:99)
at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:953)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:408)
at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1023)
at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:589)
at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:312)
at java.util.concurrent.ThreadPoolExecutor.runWorker(Unknown Source)
at java.util.concurrent.ThreadPoolExecutor$Worker.run(Unknown Source)
at java.lang.Thread.run(Unknown Source)

如何处理这个问题？

提前致谢..

Answer 1

获取request.getParameter（“ jsonVal”）后，尝试使用JSON Viewer并确定什么是特殊字符。回车+换行符与JSONTokener有关，因此，您可以对其进行修剪并使用它。

如何将带有特殊字符的json对象传递给servlet？

1 个答案: