Question

这是我设计用于检查用户名是否与数据库中的电子邮件匹配的代码。如果没有，请检查用户名。如果它不存在，请检查电子邮件。如果它不存在，请创建一个新用户名。

问题是查询每次运行并插入一个新用户!!我做错了什么？

$word = $_POST['word'];
$explination = $_POST['explination'];
$lhgat = $_POST['lhgat'];
$email = $_POST['email'];
$username = $_POST['username'];
$letterar = idar($_POST['word']);
$letteren = iden($_POST['word']);
if (!empty($word) && !empty($explination) && !empty($lhgat) && !empty($email) && !empty($username) && !empty($letterar) && !empty($letteren)) {
    //checking for username and email match
    $checkingforuserstmt = $conn->prepare('SELECT id FROM user WHERE username = username AND email = email');
    $checkingforuserstmt->execute(array(':username'   => $username, ':email' => $email));
    $checkingforuserrow = $checkingforuserstmt->fetch(PDO::FETCH_ASSOC);
    if($checkingforuserstmt->rowCount() < 0){
    //check for username only
    $checkingforuserstmt2 = $conn->prepare('SELECT id FROM user WHERE username = username');
    $checkingforuserstmt2->execute(array(':username'   => $username));
    $checkingforuserrow2 = $checkingforuserstmt2->fetch(PDO::FETCH_ASSOC);
    if($checkingforuserrow2->rowCount() < 0){   
                //check for email only
            $checkingforuserstmt3 = $conn->prepare('SELECT id FROM user WHERE email = email');
            $checkingforuserstmt3->execute(array(':email'   => $email));
            $checkingforuserrow3 = $checkingforuserstmt3->fetch(PDO::FETCH_ASSOC);
            if($checkingforuserrow3->rowCount() < 0){
                        $insertuser = $conn->prepare("INSERT INTO user VALUES('',:username,:email)");
                        $insertuser->execute(array(':username'   => $username,':email'   => $email)); }}}

Answer 1

您需要在语句中使用:，而不是绑定。例如：select * from table where field = :field不是field = field

否则你只是在说这个专栏，而不是一个价值。

检查值时，pdo if语句不起作用

1 个答案: