Question

我必须设定日，月，年，但这就是我在这里遇到的问题：

现在问题如何。（问题是在日期，日期和年份之前会有“数组......”。） “ArrayTirsdag 2013年6月11日”

想要这样： “Tirsdag 2013年6月11日”

echo "<td>" . 
                $days = array("Mandag","Tirsdag", "Onsdag","Torsdag","Fredag","Lørdag","Søndag");
                $months = array("Jan", "Feb", "Mar", "Apr", "Maj", "Jun", "Jul", "Aug", "Sep", "Okt", "Nov", "Dec");
                $timestamp = strtotime($c->pubDate);
                $dayInWeek = $days[date('N', $timestamp)-1];
                $month = $months[date('n', $timestamp)-1];
                $dayInMonth = date('d', $timestamp);
                $year = date('Y', $timestamp);
                echo $dayInWeek . ' ' .$dayInMonth. ' '.$month.' '.$year
                . "</td>";

Answer 1

当您需要.时，您的问题是;，而不是回复<td>您试图回应所有逻辑。因此，将第一行更改为echo "<td>";并进行设置。您也可以将开头<td>保存为最终结果：

// date logic
$days       = array("Mandag", "Tirsdag", "Onsdag", "Torsdag", "Fredag", "Lørdag", "Søndag");
$months     = array("Jan", "Feb", "Mar", "Apr", "Maj", "Jun", "Jul", "Aug", "Sep", "Okt", "Nov", "Dec");
$timestamp  = strtotime($c->pubDate);
$dayInWeek  = $days[date('N', $timestamp)-1];
$month      = $months[date('n', $timestamp)-1];
$dayInMonth = date('d', $timestamp);
$year       = date('Y', $timestamp);

echo "<td>$dayInWeek $dayInMonth $month $year</td>";

Answer 2

你有。第一次回声而不是逗号。

echo "<td>"; 
                $days = array(1=>"Mandag","Tirsdag", "Onsdag","Torsdag","Fredag","Lørdag","Søndag");
                $months = array(1=>"Jan", "Feb", "Mar", "Apr", "Maj", "Jun", "Jul", "Aug", "Sep", "Okt", "Nov", "Dec");
                $timestamp = strtotime($c->pubDate);
                $dayInWeek = $days[date('N', $timestamp)];
                $month = $months[date('n', $timestamp)];
                $dayInMonth = date('d', $timestamp);
                $year = date('Y', $timestamp);
                echo $dayInWeek . ' ' .$dayInMonth. ' '.$month.' '.$year
              . "</td>";

显示月/日/年 - 不起作用

2 个答案: