Question

这是我的查询...我无法使用聚合函数 - 一次计算多个表。

$qu="SELECT distinct calls.c_number, count(type) as count1,SUM(charges * duration) as total,sum(duration) as duration1,billing_details.payment as pay,packages.(count)activation as act
 FROM calls
  INNER 
    JOIN packages
    ON calls.c_number=packages.c_number 
 WHERE

 calls.date>= DATE_FORMAT( $date, '%Y/%m/01' ) AND


calls.date< DATE_FORMAT( $date + INTERVAL 1 MONTH, '%Y/%m/01') group by c_number desc having SUM(charges * duration) > 0  ";

它给了我这个错误：

FUNCTION packages.count does not exist. Check the 'Function Name Parsing and Resolution' section in the Reference Manual

Answer 1

这与PHP没有任何关系......

这与你的收入有关 -

$qu="SELECT distinct calls.c_number, count(type) as count1,SUM(charges * duration) as total,sum(duration) as duration1,billing_details.payment as pay,packages.(count)activation as act

您对“包裹。（计数）激活”的期望是什么？你的意思是count(packages.activation)？

Answer 2

试试这个

count(packages.activation)

而不是

 packages.(count)activation

无法在一个查询中对多个查询使用聚合函数

2 个答案: